[英]A segmentation fault with the use of argv
我不確定我的代碼有什么問題。 在我嘗試使用 argv 命令之前,一切正常,然后當我去執行時,我遇到了分段錯誤。 請讓我知道你的想法。
#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
using namespace std;
int main(int argc, char **argv) {
vector<string> nums;
vector<string> single {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
vector<string> second {"eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"};
vector<string> twos {"twenty", "thirty", "fourty", "fifty", "sixty", "seventy", "eighty", "ninety"};
string num;
string s;
s = argv[1];
while (s != "quit") {
nums.push_back(s);
}
int b =s.length();
int a = stoi(s);
if (a< 10){
cout << "Number" << s << "is written as" << single[a] << '\n';
}
else if (a < 100){
int temp10 = a / 10;
int temp1 = a - temp10*10;
if (temp1 == 0){
cout << "Oops! Entered a 0 in the number";
}else{
cout << "Number" << s << "is written as" << single[temp10] << single[temp1] << '\n';
}
}
else if (b == 3){
int temp100 = a / 100;
int temp10 = a - temp100*100;
temp10 = temp10 / 10;
int temp1 = a - temp100*100 - temp10*10;
if (temp10 == 1){
cout << "Oops! Entered a 1 in the tens place";
}else if (temp10 == 0 || temp1 == 0){
cout << "Oops! Entered a 0 in the number";
}else{
cout << "Number" << s << "is written as" << single[temp10] << single[temp1] << '\n';
}
}
else if (b == 4){
int temp1000 = a / 1000;
int temp100 = a - temp1000*1000;
temp100 = temp100 / 100;
int temp10 = a - temp1000*1000 - temp100*100;
temp10 = temp10 / 10;
int temp1 = a - temp1000*1000 - temp100*100 - temp10*10;
if (temp10 == 1){
cout << "Oops! Entered a 1 in the tens place";
}else if (temp1000 == 0 || temp100 == 0 || temp10 == 0 || temp1 == 0){
cout << "Oops! Entered a 0 in the number";
}else{
cout << "Number" << s << "is written as" << temp1000 << "thousand" << temp100 << "hundred" << single[temp10] << si
ngle[temp1] << '\n';
}
}
代碼的重點是接受用戶的命令行輸入並用單詞拼出數字。
我認為問題在於潛在的無限循環while (s.= "quit"){nums;push_back(s);}
,如果s真的沒有退出怎么辦? 無限循環很可能導致分段錯誤。
警告:在int a = stoi(s);
在拋出 'std::invalid_argument' what(): stoi 的實例后,您將終止調用
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