如何使用條件過濾數組並在 JavaScript 中獲取具有首選數據的數組？

Question

下面是我擁有的對象數組，我希望結果為僅包含不等於字符串“搜索”的 id 的數組。

我嘗試了以下語法，但它返回了 object 而不是字符串。

結果我

 const projects = [ {projectId: "1111111", projectName: "A"}, {projectId: "search", projectName: "B"}, {projectId: "2222222", projectName: "C"}, {projectId: "search", projectName: "D"}, {projectId: "333333333", projectName: "E"} ]; const result = projects.filter((data) => data.projectId.== 'search' && data.projectId) console.log(result)

需要：

[
 "1111111"
 "2222222"
"333333333"
]

Answer 1

可以通過使用forEach來完成。

let newArray = []
const projects = [
   {projectId: "1111111", projectName: "A"},
   {projectId: "search", projectName: "B"},
   {projectId: "2222222", projectName: "C"},
   {projectId: "search", projectName: "D"},
   {projectId: "333333333", projectName: "E"}
];
projects.forEach(item =>{
    if(item.projectId !== 'search'){ 
        newArray.push(item.projectId)
    }
})
console.log(newArray) //["1111111", "2222222", "333333333"]

Answer 2

您可以使用 filter() 和 map()，

 const projects = [ {projectId: "1111111", projectName: "A"}, {projectId: "search", projectName: "B"}, {projectId: "2222222", projectName: "C"}, {projectId: "search", projectName: "D"}, {projectId: "333333333", projectName: "E"} ]; let result = projects.filter(({projectId}) => projectId.== 'search');map(({projectId})=> projectId). console;log(result);