[英]Dynamic table with Datatables and AJAX
我正在創建一個 class 以根據傳遞給它的參數生成 CRUD 表。
我不知道如何在"ajax":
和"columns":
請求中正確傳遞我的數據,以便為我創建表格。
我正在使用以下 4 個文件:
1.- main.php
:此文件包含我的 class GenerateCrud
。
<?php
class GenerateCrud {
// Properties.
public $tableName;
public $id;
public $tableFields = array();
// Constructor.
function __construct($tableName, $id, $tableFields){
$this->tableName = $tableName;
$this->id = $id;
$this->tableFields = $tableFields;
}
public function create(){
if(empty($_SESSION['Cookie'])){
$strCookie = tempnam("/tmp", "COOKIE");
$_SESSION['Cookie'] = $strCookie;
}else{
$strCookie = $_SESSION['Cookie'];
}
// Creating the session.
$curl_handle = curl_init (SITE_URL.'/admin/login.php');
curl_setopt ($curl_handle, CURLOPT_COOKIEJAR, $strCookie);
curl_setopt ($curl_handle, CURLOPT_RETURNTRANSFER, true);
$vars= 'user=cron&pass='.CRON_PASS.'&action='.md5('login');
curl_setopt($curl_handle, CURLOPT_POSTFIELDS, $vars);
$output = curl_exec ($curl_handle);
// Loging in.
curl_setopt ($curl_handle, CURLOPT_URL, SITE_URL_ADMIN.'/alexcrudgenerator/crud/res/');
curl_setopt ($curl_handle, CURLOPT_COOKIEJAR, $strCookie);
curl_setopt ($curl_handle, CURLOPT_RETURNTRANSFER, true);
$vars= 'action=showtable&tableName='.$this->tableName.'&id='.$this->id.'&tableFields='.json_encode($this->tableFields);
curl_setopt($curl_handle, CURLOPT_POSTFIELDS, $vars);
$output = curl_exec ($curl_handle);
// I get the result.
return $output;
?>
<?php
}
}
?>
2.- res.php
:包含負責構建表的代碼。
<?php
include_once(DIR_PLUGINS.'/alexcrudgenerator/main.php');
$test = new GenerateCrud('users_test', '2', ['usuario', 'apellido1', 'apellido2', 'email']);
switch($_POST['action']){
case 'showtable':
$res = getEntireTable();
// Getting the <TH>.
$theCol = array();
foreach ($test->tableFields as $r){
$theCol[]=array('data'=>$r);
}
$myHeader = json_encode($theCol);
echo $myHeader . '<br><br>';
// Gettint the columns (data of my database).
$json = array();
foreach ($res as $data){
$json['data'][] = $data;
}
$myContent = json_encode($json);
echo $myContent;
?>
<div class="container caja">
<div class="row">
<div class="col-lg-12 col-sm-12">
<div>
<table id="tablaUsuarios" class="table table-striped table-bordered table-condensed" style="width:100%" >
<thead class="text-center">
</thead>
<tbody>
</tbody>
</table>
</div>
</div>
</div>
</div>
<script>
$(document).ready(function() {
var tableName = "<?= $test->tableName; ?>";
var id = "<?= $test->id; ?>";
var tableFields = "<?= $test->tableFields; ?>";
var tableFieldsJson = <?= json_encode($test->tableFields); ?>;
var myContent = <?= $myContent ?>;
var myHeader = <?= $myHeader ?>;
console.log(myContent);
$('#crudTable').DataTable({
"language": {"url": "//cdn.datatables.net/plug-ins/1.10.20/i18n/Spanish.json"},
"paging": true,
"lengthChange": true,
"searching": true,
"info": true,
"autoWidth": true,
"scrollX": true,
"ajax": {
"url": '<?=SITE_URL_ADMIN?>/alexcrudgenerator/crud/res/',
"method": "POST",
"data": {myContent, action: 'showtable'}
},
"columns": [
{"data": myHeader},
{"defaultContent": "<div class='text-center'><div class='btn-group'><button class='btn btn-primary btn-sm btnEditar' value='edit'><i class='material-icons'>edit</i></button><button class='btn btn-danger btn-sm btnBorrar'><i class='material-icons' value='delete'>delete</i></button></div></div>"}
]
});
})
</script>
<?php
break;
}
?>
funciones.php
:包含函數(主要是數據庫調用)。
<?php
function getEntireTable(){
global $DB;
$test = new GenerateCrud('users_test', '2', ['usuario', 'apellido1', 'apellido2', 'email']);
$myStringArray = implode(",", $test->tableFields);
$sql = "SELECT $myStringArray FROM $test->tableName";
$res = $DB->get_records($sql);
return $res;
}
?>
4.- test.php
:我將在其中創建最終表的文件(這是用戶會看到的)。
<?php
// Instanced object
$test = new GenerateCrud('users_test', 'id', ['usuario', 'apellido1', 'apellido2', 'email']);
$res = $test->create();
echo $res;
?>
我的問題:我試圖將$myHeader
和$myContent
作為"data":
來構建我的表,但我做錯了什么,我不知道是什么。
(我已經檢查過我瀏覽器的“網絡”選項卡中是否發送了任何請求,但沒有啟動任何請求)。
$myHeader
:包含我的表的 TH。$myContent
:包含我的數據庫內容。這里有一張圖片可以更清楚地看到它。
確切地說,我做錯了什么? 我以 JSON 格式正確獲得了這兩個變量。
提前致謝,伙計們,祝你周一愉快!
我認為您在 js 和 php 返回數據中遺漏了一些東西。
讓我們從 js 開始,通常我在數據表調用中設置此選項以執行 ajax 表:
"processing": true,
"serverSide": true,
"ajax":{
"url" : MyUrl,
"type": "POST",
"data": function ( d ) {
d.somedata = "some data";
},
"error": function(){
$("#table").css("display","none");
//here you can also display a error message for end user
},
},
drawCallback: function() {
//here you can call whatever function in js need to be restored
//also buttons function or tooltips or popovers
},
對於 php 數據表,希望數據以特定格式返回 json:
$requestData = $_REQUEST;//in this $requestData you will get every parameter from $_POST and $_GET and can be used in elaboration of the data of the table
$query = "myquery";
$row_db = $mysqli->query($query);
$TotalRow = $row_db->num_rows;
//Apply here the filter based on search or whatelse
$row_db = $mysqli->query($query);
$RowFiltered = $row_db->num_rows;
$rowTable = array();
while($row = $row_db->fetch_assoc()){ //or fetch_object
$nestedData = array();
$nestedData[] = $row["col1"];
$nestedData[] = $row["col2"];
//at the end of insert data in nestedData array put this
$rowTable[] = $nestedData;
}
當所有數據准備好打印出數據表時
$json_data = array(
"draw" => intval( $requestData['draw'] ), // for every request/draw by clientside , they send a number as a parameter, when they recieve a response/data they first check the draw number, so we are sending same number in draw.
"recordsTotal" => intval( $TotalRow ), // total number of records
"recordsFiltered" => intval( $RowFiltered ), // total number of records after searching, if there is no searching then totalFiltered = totalData
"data" => $rowTable // total data array
);
print_r(json_encode($json_data));
在最終結果中,從 php 打印出的“數據”與您顯示的(imge)數據確實不同。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.