從python中的二進制結果中刪除尾隨零

Question

我們有一個將十進制轉換為二進制的程序。
目標是運行程序，輸入一個值，然后以二進制形式輸出該值。

我的代碼的問題在於它在輸出二進制文件時有尾隨零。
我需要在不使用“數學”等外部庫的情況下實現這一點，所以請堅持使用內置函數。

電流輸出：

Insert a value:
5
The number fits in 1 byte and is in binary:
00000101
Insert a value:
100
The number fits in 1 byte and is in binary:
01100100
Insert a value:
280
The number fits in 16 bits and is in binary:
0000000100011000

預期輸出：

Insert a value:
5
The number fits in 1 byte and is in binary:
101
Insert a value:
100
The number fits in 1 byte and is in binary:
1100100
Insert a value:
280
The number fits in 16 bits and is in binary:
100011000

當前代碼：

def dec2bin(value, number_bits):
    result = ''
    while number_bits > 0:
        bit_value = 2 ** (number_bits - 1)
        if value >= bit_value:
            result = result + '1'
            value = value - bit_value
        else:
            result = result + '0'
        number_bits = number_bits - 1
    print(result)

input_ok = False
userinput = 0
while not input_ok:
    print('Insert a value:')
    userinput = int(input())
    if userinput > 65535:
        print('invalid, cant handle that big numbers, try again')
    else:
        input_ok = True
    if userinput < 256:
        print('The number fits in 1 byte and is in binary:')
        dec2bin(userinput, 8)
    else:
        print('The number fits in 16 bits and is in binary:')
        dec2bin(userinput, 16)

Answer 1

使用字符串格式化函數很容易（請參閱 Pranav 的評論）。 但也許在這種情況下，您希望算法處理它，並將其視為字符串是作弊。

def dec2bin(value, number_bits):
    result = ''
    starting = True
    while number_bits > 0:
        bit_value = 2 ** (number_bits - 1)
        if value >= bit_value:
            result = result + '1'
            value = value - bit_value
            starting = False
        elif not starting:
            result = result + '0'
        number_bits = number_bits - 1
    print(result)

Answer 2

由於您將值存儲為字符串，因此您可以使用

result.lstrip('0')

從您的答案中刪除前導零。