如果字符串包含特定字符，如何從字符串中刪除單詞？

Question

好的，假設我的字符串包含以下內容： "$$$FOOD WATERMELON" 。 如何從字符串中刪除"$$$FOOD" ？

假設我在列表中有字符串：

data_list = ["$$$FOOD WATERMELON", "$$$STORY I walked to the local store"]

我在代碼中的方法拆分列表中的元素，然后遍歷列表內的列表並刪除任何包含"$$$"元素，如果不是因為.split()函數拆分每個單詞，因此列表最終將如下所示： [["WATERMELON"],["I","walked","to","the","local,"store"]]這不是最優的，因為那樣我將不得不加入列表中的元素，這需要更多的時間。

基本上，我唯一想知道的是：如果字符串中包含"$$$"我該如何刪除它。 所以這個字符串： word = "$$$STORY I walked to the store"將變成"I walked to the store"

對不起，如果這令人困惑

Answer 1

你可以試試這個：

>>> word = "$$$STORY I walked to the store"
>>> if word.startswith('$',0,word.index(' ')):
        word=word[word.index(' ')+1:]

>>> word
'I walked to the store'

以下是使用列表和函數的外觀：

def check_word(word):
    if word.startswith('$',0,word.index(' ')):
        return word[word.index(' ')+1:]
data_list = ["$$$FOOD WATERMELON", "$$$STORY I walked to the local store"]
list2=[check_word(x) for x in data_list]
print(list2)

Answer 2

試試這個。

import re

data_list = ["$$$FOOD WATERMELON", "$$$STORY I walked to the local store"]
output = [re.sub(r'\s*[$]+\w+\s*', '', x) for x in data_list]

這給了我以下輸出：

['WATERMELON', 'I walked to the local store']

這是正則表達式定義：

\s
matches any whitespace character (equivalent to [\r\n\t\f\v ])
* matches the previous token between zero and unlimited times, as many times as possible, giving back as needed (greedy)
Match a single character present in the list below [$]
+ matches the previous token between one and unlimited times, as many times as possible, giving back as needed (greedy)
$ matches the character $ with index 3610 (2416 or 448) literally (case sensitive)
\w
matches any word character (equivalent to [a-zA-Z0-9_])
+ matches the previous token between one and unlimited times, as many times as possible, giving back as needed (greedy)
\s
matches any whitespace character (equivalent to [\r\n\t\f\v ])
* matches the previous token between zero and unlimited times, as many times as possible, giving back as needed (greedy)

Answer 3

此代碼檢查並確保任何單詞都沒有子字符串，而不僅僅是像其他一些答案一樣的第一個單詞。

輸出：

['WATERMELON', 'I walked to the local store']

代碼：

data_list = ["$$$FOOD WATERMELON", "$$$STORY I walked to the local store"]

for word in range(len(data_list)):
  temp1 = data_list[word].split(" ")
  finished = False
  while not (finished):
      for temp2 in range(len(temp1)):
          if "$$$" in temp1[temp2]:
              temp1.pop(temp2)
              break
          finished = True
  data_list[word] = ' '.join(temp1)

print(data_list)