[英]How to fix the logic of "Guess the Movie" Game i have written in Python
所以,我正在為 python 做一個在線課程,並且有一個“猜電影”游戲的測試示例代碼。 然而,我試圖按照幾乎相同的邏輯自己編寫它,但似乎有一個錯誤,多個字母被解鎖而不是一個。
例如:ROB,輪到你了
你的信:o
正如你所看到的,而不是顯示只有字母“o”被解鎖,最后一個字母“l”也被解鎖,即使我之前沒有輸入它。這里的電影叫做“靈魂”。 輸入字母“S”后顯示:
按 1 猜測電影或按 2 解鎖另一個角色 2 你的字母:S
靈魂
電影已完全解鎖。如果你能找到我代碼中的錯誤,請給我一個解決方案。 我的代碼:
import random
Films=["Deadpool","Avengers Endgame","Drishyam","Hera Pheri","Munna Bhai MBBS","Justice League","The Dark Knight","Cars","Titanic","Haseena Man Jayegi","Uri Surgical Strike","Guardians of the Galaxy","Interstellar","Inception","The Great Gatsby","John Wick","Spiderman Homecoming","Bajirao Mastani","Nobody","Life of Pi","Krish","Golmaal","Housefull","Zindagi Na Milegi Dobara","3 idiots","Dangal","Badshah","The Shawshank Redemption","Frozen","Soul","Despicable Me","Minions","Crossroads"]
def create_question(Movie):
n=len(Movie)
letters=list(Movie)
temp=[]
for i in range(n):
if letters[i]== " ":
temp.append(" ")
else:
temp.append("*")
Q =" ".join(str(x) for x in temp)
return Q
def is_present(letter,Movie):
c=Movie.count(letter)
if c==0:
return False
else:
return True
def unlock(Q,picked_Movie,letter):
ref=list(picked_Movie)
Q_list=list(Q)
temp=[]
n=len(picked_Movie)
for i in range(n):
if ref[i]==" " or ref[i]==letter:
temp.append(ref[i])
else:
if Q_list[i]=="*":
temp.append("*")
else:
temp.append(ref[i])
Q_new =" ".join(str(x) for x in temp)
return Q_new
def game():
pA=input("Player 1 Name:")
pB=input("Player 2 Name:")
pp1=0
pp2=0
turn=0
willing=True
while willing:
if turn%2==0:
print(pA,",your turn")
picked_Movie=random.choice(Films)
Q=create_question(picked_Movie)
print(Q)
modified_Q=Q
not_said=True
while not_said:
letter=input("Your letter:")
if(is_present(letter,picked_Movie)):
modified_Q = unlock(modified_Q,picked_Movie,letter)
print(modified_Q)
d=int(input("Press 1 to guess the movie or 2 to unlock another character"))
if d==1:
ans=input("Answer:")
if ans==picked_Movie:
print("Yay! Correct answer.")
pp1=pp1+1
print(pA,"'s Score=",pp1)
not_said=False
else:
print("Wrong Answer, Try again...")
else:
print(letter,'not found')
c=int(input("press 1 to continue or 0 to exit:"))
if c==0:
print(pA,",Your Score is",pp1)
print(pB,",Your Score is",pp2)
print("Thank you for playing, have a nice day!!!")
willing=False
else:
print(pB,",your turn")
picked_Movie=random.choice(Films)
Q=create_question(picked_Movie)
print(Q)
modified_Q=Q
not_said=True
while not_said:
letter=input("Your letter:")
if(is_present(letter,picked_Movie)):
modified_Q = unlock(modified_Q,picked_Movie,letter)
print(modified_Q)
d=int(input("Press 1 to guess the movie or 2 to unlock another character:"))
if d==1:
ans=input("Answer:")
if ans==picked_Movie:
print("Yay! Correct answer.")
pp2=pp2+1
print(pB,"'s Score=",pp2)
not_said=False
else:
print("Wrong Answer, Try again...")
else:
print(letter,'not found')
c=int(input("press 1 to continue or 0 to exit:"))
if c==0:
print(pA,",Your Score is",pp1)
print(pB,",Your Score is",pp2)
print("Thank you for playing, have a nice day!!!")
willing=False
turn=turn+1
game()
幾次運行你的代碼后,測試它,我發現了問題:
里面unlock
function,你做錯了:
for i in range(n):
if ref[i]==" " or ref[i]==letter:
temp.append(ref[i])
else:
if Q_list[i]=="*":
temp.append("*")
else:
temp.append(ref[i])
您只檢查了Q_list[i]
是否有*
。 但是如果里面有" "
怎么辦? 然后你會無緣無故地收到來自ref[i]
的另一封信!
您唯一需要做的就是修改 if 語句:
for i in range(n):
if ref[i]==" " or ref[i]==letter:
temp.append(ref[i])
else:
if Q_list[i]=="*" or Q_list[i] == " ": # <-- FIX HERE
temp.append("*")
else:
temp.append(ref[i])
編輯:
我看到在某些情況下我的代碼仍然無法正常工作,這就是為什么:如果電影名稱中有" "
,那么Q_list
將比ref
大,這會給我們帶來意想不到的結果。
您可以輕松修復它,刪除*
之間的所有" "
。 到處都有:
" ".join(str(x) for x in temp)
這在您的代碼中(實際上是兩次),將其更改為:
"".join(str(x) for x in temp)
我剛剛更改了unlock()方法,如下所示(更改在注釋中提到) :
def unlock(Q,picked_Movie,letter):
ref=list(picked_Movie)
Q_list=list(Q)
temp=[]
n=len(picked_Movie)
for i in range(n):
if ref[i]==" " or ref[i]==letter:
temp.append(ref[i])
else:
if Q_list[i]=="*" or Q_list[i] == " ": #Added 1 more condition Q_list[i] == " "
temp.append("*")
else:
temp.append(ref[i])
Q_new ="".join(str(x) for x in temp) #Replaced " " to ""
return Q_new
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