如何顯示開放時間？

Question

我試圖顯示工作時間/天的間隔，它應該是這樣的：

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我有表，其中我存儲天數時，開啟時間和關閉時間的每一天

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然后我創建了query =>

var groups = from s in this.OpenTimes
orderby s.Day
group s by new { s.Till, s.Start } into gr
select new
{
    Time = gr.Key.Start + "-" + gr.Key.Till,
    Days = this.OpenTimes
        .Where(o => o.Start == gr.Key.Start && o.Till == gr.Key.Till)
        .OrderBy(d => d.Day).Select(d => d.Day).ToArray()
};

此查詢提供包含在此時間范圍內的所有分組時間間隔和天數但是我遇到了問題 - 我創建了代表此組的下半部分，但它無法正常工作。 也許有人可以向我解釋所需的視野或顯示開放時間的基本邏輯。

謝謝你的建議......

Answer 1

下一步方法對我有用：

結果屏幕

  public string OpeningTimesString
      {
         get
         {
            if (!this.OpeningTimes.IsLoaded)
               this.OpeningTimes.Load();
            var groups = (from s in this.OpeningTimes
                       orderby s.Day, s.Start, s.Stop
                       group s by new { Stop = formatTime(s.Stop), Start = formatTime(s.Start), s.Day } into gr
                       select new
                       {
                          Time = gr.Key.Start + "-" + gr.Key.Stop,
                          Day = gr.Key.Day
                       }).ToList();
            string result = "";
            int tmp = 1;
            for (int i = 0; i < groups.Count(); i++)
            {


               //One one = new One();
               bool exit = false;
               tmp = i;
               while (exit == false)
               {
                  if (i + 1 < groups.Count && groups[i].Time.Equals(groups[i + 1].Time))
                  {
                     i++;
                  }
                  else
                  {
                     if (tmp != i)
                        result += (NormalDayOfWeek)(groups[tmp].Day - 1) + "-" + (NormalDayOfWeek)(groups[i].Day - 1) + " : " + groups[i].Time + "<br />";
                     else
                        result += (NormalDayOfWeek)(groups[i].Day - 1) + " : " + groups[i].Time + "<br />";
                     exit = true;
                  }
               }
            }

            if (result.IsNotNull())
               return result;
            else
               return "[%Not yet defined]";
         }
      }