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[英]How to separate a Python list into two lists, according to some aspect of the elements
[英]How to separate a list into two lists according to the objects' types using isinstance()?
使用這樣的列表: ["apple", "orange", 5, "banana", 8, 9]
如何使用 isinstance() 將字符串 (str) 放入一個列表並將整數 (int) 放入另一個列表?
這邊走 -
a = ["apple", "orange", 5, "banana", 8, 9]
b1 = [el for el in a if isinstance(el, str)]
b2 = [el for el in a if isinstance(el, int)]
使用列表理解:
lst = ["apple", "orange", 5, "banana", 8, 9]
strings = [s for s in lst if isinstance(s, str)]
integers = [n for n in lst if isinstance(n, int)]
或者,為了避免使用兩個for
循環,您也可以根據需要循環遍歷列表和 append 到相應的列表:
strings = list()
integers = list()
for l in lst:
if isinstance(l, str):
strings.append(l)
elif isinstance(l, int):
integers.append(l)
這是使用itertools.groupby
和type
的通用解決方案。
我在這里選擇返回一個字典,因為它很容易通過名稱獲取元素,但您也可以返回一個列表列表。
from itertools import groupby
l = ["apple", "orange", 5, "banana", 8, 9]
grouper = lambda x: type(x).__name__
{k:list(g) for k,g in groupby(sorted(l, key=grouper), grouper)}
output:
{'int': [5, 8, 9], 'str': ['apple', 'orange', 'banana']}
ints, strings = [list(g) for k,g in groupby(sorted(l, key=grouper), grouper)]
output:
>>> ints
[5, 8, 9]
>>> strings
['apple', 'orange', 'banana']
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