如何將一維數組的具體規律轉換成二維數組？

Question

像這樣

string[]  strarry = [12, 34, A1, FE, 12, 34, EA, 0, FE]

12是開始， FE是結束，變成

string strarry = [[12,34,A1,FE], [12,34,EA,0,FE]];

12到FE的距離不一定是固定的（ 4 ）

我該怎么做？ 謝謝

Answer 1

如果我理解正確（您想從序數一 - string[]獲取鋸齒狀數組string[][] string[] ），您可以嘗試Linq以便將GroupBy項轉換為子數組：

  using System.Linq;

  ...

  string[] strarry = new string[]
    {"12", "34", "A1", "FE", "12", "34", "EA", "0", "FE"};

  // Here we exploit side effects, be careful with them
  int groupIndex = 0;

  string[][] result = strarry
    .GroupBy(value => value == "FE" ? groupIndex++ : groupIndex)
    .Select(group => group.ToArray())
    .ToArray();

我們來看一下：

  string report = string.Join(Environment.NewLine, result
    .Select(line => "[" + string.Join(", ", line) + "]"));

  Console.Write(report);

結果：

[12, 34, A1, FE]
[12, 34, EA, 0, FE]

Answer 2

我不確定此代碼對您的適用性如何，但也許它可以幫助您找到某個地方。 祝你好運！

        var strarry = "12, 34, A1, FE, 12, 34, EA, 0, FE";
        var splittedArrays = strarry.Split(", FE", StringSplitOptions.RemoveEmptyEntries);

        for (int i = 0; i < splittedArrays.Length; i++)
        {
            if (splittedArrays[i][0].Equals(','))
            {
                splittedArrays[i] = splittedArrays[i].Substring(2);
            }

            splittedArrays[i] += ", FE";
            Console.WriteLine(splittedArrays[i]);
        }