[英]C++: Program get terminated at mid of taking input string
我的程序正在從用戶那里獲取字符串輸入。 使用fgets()
函數,但我也嘗試過gets()
和scanf("%[^\\n]s", str)
,但程序仍然在一半處終止。
Book* create_book()
{
Book* new_book;
char* title;
char* author;
char* publisher;
double price;
int stock;
printf("\nPublisher: ");
fgets(publisher, 50, stdin);
printf("\nTitle: ");
fgets(title, 50, stdin);
printf("\nAuthor: ");
fgets(author, 50, stdin);
printf("\nPrice: ");
cin >> price;
printf("\nStock Position: ");
cin >> stock;
*new_book = Book(author, title, publisher, price, stock);
printf("\nCreated");
return new_book;
}
程序在僅接受兩個輸入后終止。
這是輸出:
Publisher: Pearson
Title: The power of subconcious mind
您沒有分配任何內存來讀取用戶輸入。 您的char*
和Book*
指針未初始化並且沒有指向任何有意義的地方。
試試這個:
Book* create_book()
{
Book* new_book;
char title[50];
char author[50];
char publisher[50];
double price;
int stock;
printf("\nPublisher: ");
fgets(publisher, 50, stdin);
printf("\nTitle: ");
fgets(title, 50, stdin);
printf("\nAuthor: ");
fgets(author, 50, stdin);
printf("\nPrice: ");
cin >> price;
printf("\nStock Position: ");
cin >> stock;
new_book = new Book(author, title, publisher, price, stock);
printf("\nCreated");
return new_book;
}
Book *book = create_book();
// use book as needed...
delete book;
話雖如此,將 C 習語與 C++ 習語混合在一起是個壞主意。 擁抱 C++。 您應該將std::cin
和std::cout
用於用戶 I/O。 和std::string
而不是char[]
字符串。 和智能指針而不是原始指針。
嘗試這個:
unique_ptr<Book> create_book()
{
unique_ptr<Book> new_book;
string title;
string author;
string publisher;
double price;
int stock;
cout << "\nPublisher: ";
getline(cin, publisher);
cout << "\nTitle: ";
getline(cin, title);
cout << "\nAuthor: ";
getline(cin, author);
cout << "\nPrice: ";
cin >> price;
cout << "\nStock Position: ";
cin >> stock;
new_book = make_unique<Book>(author, title, publisher, price, stock);
cout << "\nCreated";
return new_book;
}
auto book = create_book();
// use book as needed...
// no delete needed
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