在 tauri_hotkey 中單擊時刪除偵聽器

Question

添加一個鍵盤鍵偵聽器，當按下該鍵時，我想刪除該偵聽器，我使用這個板條箱

添加監聽器工作正常

use tauri_hotkey;

fn main() {
    let mut hotkey = tauri_hotkey::HotkeyManager::new();
    let key = tauri_hotkey::Hotkey {
        keys: vec![tauri_hotkey::Key::A],
        modifiers: vec![],
    };
    hotkey
        .register(key, || {
            println!("You pressed A",);
        })
        .unwrap();

    loop {} // infinate loop for prevent main from existing
}

單擊鍵時刪除偵聽器

    hotkey
        .register(key, || { 
            hotkey.unregister(&key).unwrap();
        })
        .unwrap();

它給出了一個編譯錯誤說

cannot borrow `hotkey` as mutable more than once at a time
    
second mutable borrow occurs hererustc(E0499)
main.rs(29, 5): second mutable borrow occurs here
main.rs(30, 24): first mutable borrow occurs here
main.rs(32, 14): first borrow occurs due to use of `hotkey`

有沒有辦法解決這個問題，訪問閉包內的熱鍵？

Answer 1

注冊簽名甚至不允許自己更改“熱鍵”。 首先是“&mut self”約束，其次是應該是“靜態”的回調

  pub fn register<F>(&mut self, hotkey: Hotkey, callback: F) -> Result<()>
  where
    F: 'static + FnMut() + Send

一種方法可能是這樣的

use std::sync::{Arc, Mutex};
use tauri_hotkey;

fn main() {
    let mut hotkey = tauri_hotkey::HotkeyManager::new();

    let key = tauri_hotkey::Hotkey {
        keys: vec![tauri_hotkey::Key::A],
        modifiers: vec![],
    };

    let is_pressed = Arc::new(Mutex::new(false));
    let is_p = Arc::clone(&is_pressed);
    hotkey
        .register(key.clone(), move || {
            let mut is_p = is_p.lock().unwrap();
            *is_p = true;
        })
        .unwrap();

    loop {
        let pressed = Arc::clone(&is_pressed);
        let mut pressed = pressed.lock().unwrap();

        if *pressed {
            hotkey.unregister(&key).unwrap();
            *pressed = false;
        }
    } // infinate loop for prevent main from existing
}