[英]python counting occurrences value in nested dictionary
我一直無法找到計算值的解決方案。
data = {"members": {
"1": {
"name": "burek",
},
"status": {
"description": "Online",
"state": "Busy",
"color": "green",
},
"position": "seller"
},{
"2": {
"name": "pica",
},
"status": {
"description": "Offline",
"state": "Idle",
"color": "red",
},
"position": "waiting"
},{
"3": {
"name": "strucko",
},
"status": {
"description": "Online",
"state": "Busy",
"color": "green",
},
"position": "backside"
}}
現在我可以數鑰匙了:
def count(d, k):
return (k in d) + sum(count(v, k) for v in d.values() if isinstance(v, dict))
但是在找出計算價值的方法時遇到很多麻煩。
print(count(data, 'Online'))
我希望結果是 2。
一種方法:
def count(d, k):
current = 0
for di in d.values():
if isinstance(di, dict):
current += count(di, k)
elif k == di:
current += 1
return current
res = count(data, "Online")
print(res)
輸出
2
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