[英]C++ candidate function not viable
我嘗試打印出一個空向量,但收到以下錯誤:
/Library/Developer/CommandLineTools/SDKs/MacOSX.sdk/usr/include/c++/v1/ostream:220:20: note: candidate function not viable: no known conversion from 'vector<int>' to 'basic_streambuf<std::basic_ostream<char>::char_type> *' (aka 'basic_streambuf<char> *') for 1st argument
basic_ostream& operator<<(basic_streambuf<char_type, traits_type>* __sb);
^
/Library/Developer/CommandLineTools/SDKs/MacOSX.sdk/usr/include/c++/v1/ostream:223:20: note: candidate function not viable: no known conversion from 'vector<int>' to 'std::nullptr_t' for 1st argument
basic_ostream& operator<<(nullptr_t)
我也嘗試過std::cout << vec << std::endl;
但它仍然不起作用。
這是我的代碼:
#include <iostream>
#include <string>
#include <fstream>
#include <vector>
using namespace std;
int main() {
vector <int> vec(5);
cout << vec << endl;
return 0;
}
不要掛斷無法轉換為std::nullptr_t
的問題。 該錯誤基本上意味着您的向量類型的 output stream 運算符沒有過載。 因此,您必須為向量實現自己的 output function ,如下所示:
#include <iostream>
#include <string>
#include <vector>
template<typename type_t>
std::ostream& operator<<(std::ostream& os, const std::vector<type_t>& vector)
{
bool comma = false;
for (const auto& item : vector)
{
if (comma) std::cout << ", ";
std::cout << item;
comma = true;
}
std::cout << "\n";
return os;
}
int main()
{
std::vector<int> vec{ 1,2,3,4,5 };
std::cout << vec;
return 0;
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.