將一個 function 的 output 轉換為數組並將值輸入到另一個 function 中的變量

Question

For one of ruby programming logic, am trying to convert the string output of one function into an array and from array have to feed the values to the variables declared in other function of the program

//response.each do |instance |
  print "#{instance.private_ip_address}"
  print "\n"
  end
//

10.1.1.1
10.1.1.2
10.1.1.3

此 output 應轉換為數組並作為同一程序的單獨 function 中的值提供

def run_me
    ::
    ::
    filter_pattern = '[w1,w2,w3,w4,w5,w6!="*#{array[0]}*"&&w6!="*#{array[1]}*&&w6!="*#{array[2]}*"]'

所以filter_pattern的output應該如下

   '[w1,w2,w3,w4,w5,w6!="*10.1.1.1*"&&w6!="*10.1.1.2*"&&w6!="*10.1.1.3*"]'

Answer 1

# Mocked responses for the sake of the example..
responses = [
  OpenStruct.new(request_type: 'GET', private_ip_address: '10.1.1.1'),
  OpenStruct.new(request_type: 'GET', private_ip_address: '10.1.1.2'),
  OpenStruct.new(request_type: 'GET', private_ip_address: '10.1.1.3')
]

data_of_ips = [] # Storing ips in this array from the loop for later usage in run_me method

responses.each do |instance|
  data_of_ips << instance.private_ip_address
end

# Now calling the run_me and pass the array as argument

run_me(data_of_ips)

# replace it in your filter like this
def run_me(ips)
  # 
  # 
  filter_pattern = '[w1,w2,w3,w4,w5,w6!="*#{ips[0]}*"&&w6!="*#{ips[1]}*&&w6!="*#{ips[2]}*"]'^Z
end