[英]How to remove specific (side-by-side) duplicates in r?
假設我有以下字符串:
l1 = c(0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 0, 1, 1, 1, 1, 0, 1)
而我只想保留“FIRST new 1”,也就是我對上面強的渴望結果是:
l1 = c(0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1)
我試圖移動和減去列表,無論不是 1,都設置為 0; 但這種方式行不通。
你可以試試(基礎R
方式)
x <- c(0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 0, 1, 1, 1, 1, 0, 1)
y <- rle(x)
z<- cumsum(y$lengths)[y$values == 0] + 1
w <- rep(0, length(x))
w[z] <- 1
w
[1] 0 0 1 0 0 0 1 0 0 0 0 1 0 0 0 0 1
dplyr
方式
library(dplyr)
library(xts)
library(data.table)
x <- data.frame(
l1 = c(0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 0, 1, 1, 1, 1, 0, 1)
)
x %>%
mutate(y = rleid(l1)) %>%
group_by(y) %>%
mutate(l1 = ifelse((y %% 2) == first(l1) & row_number(y)>1, 0, l1)) %>%
ungroup %>%
select(-y) %>%
pull(l1)
[1] 0 0 1 0 0 0 1 0 0 0 0 1 0 0 0 0 1
笨拙的方式
bool IsNewOneAppeared = 0
for(int i;i<c.length;i++)
{
if(IsNewOneAppeared )
c[i]= 0;
else if(c[i] equal 1)
{
keep 1;
IsNewOneAppeared =1;
}
}
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