在 Python 中，我似乎無法在列表中找到相同的項目

Question

tuple= [['nike airjordan kahverengi', 42, 6],['nike airjordan sarı', 42, 10], ['nike airjordan mavi', 42, 8],['nike airjordan yeşil', 42, 9] ['nike airjordan sarı', 42, 10]]

def getOrderList(self):
        orderSplit = ''.join(self.orderText).splitlines()
        productList = []
        for idx, i in enumerate(orderSplit, start = 0):
            if(idx > self.starting_point):
                if i == '@':
                    break
                else:    
                    productList.append([i.rstrip(i[-3:]), int(i[-2:]),idx])
            

        return productList

這是獲得元組的 function

orderList = self.product.getOrderList()

在這里我從現在開始在元組中尋找相同的

Answer 1

您可以 map 您的列表到元組並使用collections.Counter ：

lsts = [['nike airjordan kahverengi', 42, 6],['nike airjordan sarı', 42, 10],
        ['nike airjordan mavi', 42, 8],['nike airjordan yeşil', 42, 9],
        ['nike airjordan sarı', 42, 10]]

from collections import Counter
counts = Counter(map(tuple, lsts))

for k,v in counts.items():
    print(list(k), 'appears', v, 'time(s).')

Output：

['nike airjordan kahverengi', 42, 6] appears 1 time(s).
['nike airjordan sarı', 42, 10] appears 2 time(s).
['nike airjordan mavi', 42, 8] appears 1 time(s).
['nike airjordan yeşil', 42, 9] appears 1 time(s).