如何遞歸地從孩子 c# 中獲取所有父母？

Question

有所有視圖位置（比如說 100，這些是 TreeView 的位置）：Id、Name、ParentId 1 Root Null 2 Semi-root 1 3 Semi-semi-root 2 4.....

還有一些數據，我們只從另一個請求中收到與我們的值相對應的位置：Id、Name、ParentId 22 Location1 12 36 Location38 21 99 Location38 3

需要獲取我們從請求中獲得的數據的所有父層次結構。 有 class：

public class TreeViewNode {
  public Guid Id {get; set;}
  public string Name {get; set;}
  public Guid ParentId {get; set;}
}

測試數據：

 private IEnumerable<TreeViewNode> SeedData()
        {
            return new List<TreeViewNode>
            {
                new()
                {
                    Id = 1,
                    Name = "Root",
                    ParentId = null
                },
                new()
                {
                    Id = 2,
                    Name = "Semi-root",
                    ParentId = 1
                },
                new()
                {
                    Id = 3,
                    Name = "Semi te",
                    ParentId = 2
                },
                new()
                {
                    Id = 4,
                    Name = "Semi oi",
                    ParentId = 2
                },
                new()
                {
                    Id = 5,
                    Name = "Child",
                    ParentId = 3
                },
                new()
                {
                    Id = 6,
                    Name = "Child 1",
                    ParentId = 4
                },
                new()
                {
                    Id = 7,
                    Name = "Child 2",
                    ParentId = 1
                },
                new()
                {
                    Id = 8,
                    Name = "Child 3",
                    ParentId = 1
                },
                new()
                {
                    Id = 9,
                    Name = "Child 4",
                    ParentId = 1
                },
                new()
                {
                    Id = 10,
                    Name = "Child 6",
                    ParentId = 2
                }
            };
        }

從請求中獲得的示例數據：

 var dataFromRequest = new List<TreeViewNode>
            {
                new()
                {
                    Id = 8,
                    Name = "Child 3",
                    ParentId = 1
                },
                new()
                {
                    Id = 10,
                    Name = "Child 6",
                    ParentId = 2
                },
                new()
                {
                    Id = 33,
                    Name = "Child",
                    ParentId = 3
                },
                new()
                {
                    Id = 4,
                    Name = "Semi oi",
                    ParentId = 2
                }
            };

結果需要得到這樣的父母名單：

Id Name ParentId
1 Root Null
2 Semi-root 1
3 Semi te 2

這里可以是5個或更多級別的父母

Answer 1

像這樣的東西

// create Dictionary for lookups
var lookup = dataFromRequest.ToDictionary(x => x.Id.Value, x => x);

var lookFor = new TreeViewNode()
{
    Id = 6,
    Name = "Child 1",
    ParentId = 4
};

// get all the parents
GetParents(lookup, lookFor);

獲取所有父母的幫助方法

private void GetParents(Dictionary<int, TreeViewNode> lookup, 
                                TreeViewNode lookFor)
{
    while (lookFor != null)
    {
        // Alternative: Add lookFor to List<TreeViewNode> here and return at 
        // the end of the method
        Debug.WriteLine($"{lookFor.Id} {lookFor.Name} {lookFor.ParentId}");

        if (lookFor.ParentId == null)
            break;

        // cast ParentId to corrent dataType here Guid or int
        lookup.TryGetValue((int)lookFor.ParentId, out var parentNode);
        lookFor = parentNode;
    }

}

當您獲得更多IEnumerable<TreeViewNode>時，請記住讓您的查找字典保持最新

您可以做的另一件事是在TreeViewNode中設置父節點，如下所示：

public class TreeViewNode {
    ...
    // set ParentNode by lookup in the Dictionary once
    public TreeViewNode ParentNode {get; set;}
}