如何在一個帶有while function的循環內創建一個循環？

Question

有時在搜索第二個按鈕時，網站無法正確加載，因此我想檢查第一個按鈕是否可用，這樣我就知道網站加載正確。 目前它只檢查一次第一個按鈕是否可用，如果為真則停止循環。 那么我該如何循環這段代碼，以便它每次都檢查第一個按鈕是否可用，即使在運行 else function 中的 while not 代碼之后也是如此。

firstbutton 和 secondbutton 之后的代碼不能相同，因此像 Prophet's answer 這樣的代碼不起作用。

while not (driver.find_elements(By.XPATH, "firstbutton")):
    driver.get('different url')
    driver.refresh()
else: 
    secondButton = driver.find_elements(By.XPATH, "secondbutton")
    while not (driver.find_elements(By.XPATH, "secondbutton")):
        time.sleep(1)
        driver.refresh()
secondbutton[0].click()

Answer 1

# wait while firstbutton is present
while not (driver.find_elements(By.XPATH, "firstbutton")):
    driver.get('different url')
    driver.refresh()

# firstbutton is found

secondButton = driver.find_elements(By.XPATH, "secondbutton")
# keep waiting and refreshing till we have both first and second button
while (not (driver.find_elements(By.XPATH, "secondbutton")) or
       not (driver.find_elements(By.XPATH, "firstbutton"))):         
    time.sleep(1)
    driver.refresh()
secondbutton[0].click()

應該適用於您的情況。

Answer 2

看起來您正在嘗試刷新頁面，直到 first_button和second_button 都出現在那里？
如果是這樣，您只需要刷新，直到找到兩個元素。
像這樣的東西：

first_button = driver.find_elements(By.XPATH, "firstbutton")
second_button = driver.find_elements(By.XPATH, "secondbutton")
while not (first_button and second_button):
    first_button = driver.find_elements(By.XPATH, "firstbutton")
    second_button = driver.find_elements(By.XPATH, "secondbutton")
    time.sleep(1)
secondbutton[0].click()