對 SQL 中的字符串數組進行排序

Question

我在 SQL Server 2019 中有一列要排序的字符串

Select * from ID 

[7235, 6784] 
[3235, 2334] 
[9245, 2784] 
[6235, 1284] 

試圖得到以下結果：

[6784, 7235]
[2334, 3235]
[2784, 9245]
[1284, 6235]

Answer 1

鑒於此示例數據：

CREATE TABLE dbo.ID(ID int IDENTITY(1,1), SomeCol varchar(64));

INSERT dbo.ID(SomeCol) VALUES
('[7235, 6784]'),
('[3235, 2334]'), 
('[9245, 2784]'),
('[6235, 1284]');

您可以運行此查詢：

;WITH cte AS 
(
  SELECT ID, SomeCol, 
      i = TRY_CONVERT(int, value), 
      s = LTRIM(value)
    FROM dbo.ID CROSS APPLY 
    STRING_SPLIT(PARSENAME(SomeCol, 1), ',') AS s
)
SELECT ID, SomeCol, 
  Result = QUOTENAME(STRING_AGG(s, ', ') 
           WITHIN GROUP (ORDER BY i))
FROM cte
GROUP BY ID, SomeCol
ORDER BY ID;

Output：

ID	一些科爾	結果
1	[7235, 6784]	[6784, 7235]
2	[3235, 2334]	[2334, 3235]
3	[9245, 2784]	[2784, 9245]
4	[6235, 1284]	[1284, 6235]

• 示例db<>fiddle

Answer 2

源表有一列包含 JSON 數組。

這就是為什么通過 SQL 服務器 JSON API 處理它是一個完美的案例。

SQL

-- DDL and sample data population, start
DECLARE @tbl TABLE (ID int IDENTITY PRIMARY KEY, jArray NVARCHAR(100));
INSERT @tbl (jArray) VALUES
('[7235, 6784]'),
('[3235, 2334]'), 
('[9245, 2784]'),
('[6235, 1284]');
-- DDL and sample data population, end

SELECT t.*
    , Result = QUOTENAME(STRING_AGG(j.value, ', ') 
           WITHIN GROUP (ORDER BY j.value ASC))
FROM @tbl AS t
    CROSS APPLY OPENJSON(t.jArray) AS j
GROUP BY t.ID, t.jArray
ORDER BY t.ID;

Output

+----+--------------+--------------+
| ID |    jArray    |    Result    |
+----+--------------+--------------+
|  1 | [7235, 6784] | [6784, 7235] |
|  2 | [3235, 2334] | [2334, 3235] |
|  3 | [9245, 2784] | [2784, 9245] |
|  4 | [6235, 1284] | [1284, 6235] |
+----+--------------+--------------+