如何使用 GAS 從數組的 arrays 中刪除多個元素？

Question

問題

我有一個包含空列的數據集。 該數據集是通過定義范圍的getValues()獲得的。 由於我將存儲此數據集，因此我想在此之前刪除空列，因此需要刪除這些列。

數據集樣本

[
["120/1","2022-02-01T03:00:00.000Z","2022-02-01T03:00:00.000Z","Cartão Crédito","","Sicredi","","Visa","","1 + 6x","","1 de 7",100],
["120/2","2022-02-01T03:00:00.000Z","2022-03-01T03:00:00.000Z","Cartão Crédito","","Sicredi","","Visa","","1 + 6x","","2 de 7",100]
]

邪惡的代碼片段（對我來說）

const colsVazias = [11, 9, 7, 5];//"Columns/elements" to be removed
    for (let i = colsVazias.length - 1; i >= 0; i--) {
      for (let r = 0; r < pagtos.length; r++) {
        pagtos[r].splice(colsVazias[i], 1)
      }
    }

我也試過這個（借自@nnnnnn），但我無法調整它以滿足這里的需求。 很可能，因為我們在這里處理不同的維度......

var valuesArr = ["v1","v2","v3","v4","v5"],
    removeValFromIndex = [0,2,4];    

for (var i = removeValFromIndex.length -1; i >= 0; i--)
   valuesArr.splice(removeValFromIndex[i],1);

預期 output：

[
["120/1","2022-02-01T03:00:00.000Z","2022-02-01T03:00:00.000Z","Cartão Crédito","Sicredi","Visa","1 + 6x","1 de 7",100],
["120/2","2022-02-01T03:00:00.000Z","2022-03-01T03:00:00.000Z","Cartão Crédito","Sicredi","Visa","1 + 6x","2 de 7",100]
]

感謝任何幫助！

Answer 1

一個簡單的地圖/過濾器組合就可以了

 let pagatos = [ ["120/1","2022-02-01T03:00:00.000Z","2022-02-01T03:00:00.000Z","Cartão Crédito","","Sicredi","","Visa","","1 + 6x","","1 de 7",100], ["120/2","2022-02-01T03:00:00.000Z","2022-03-01T03:00:00.000Z","Cartão Crédito","","Sicredi","","Visa","","1 + 6x","","2 de 7",100] ]; let remove = [10, 8, 6, 4] pagatos = pagatos.map(p => p.filter((v,i) =>.remove.includes(i))) console.log(pagatos)