[英]How to mutate a list of objects in an array as an argument in GraphQL completely
我不能完全改變對象列表,因為只有數組的最后一個元素會被改變。
已經完美工作的是,如果我像這里一樣手動將每個元素 ({play_positions_id: ...}) 放入數組中:
mutation CreateProfile {
__typename
create_profiles_item(data: {status: "draft", play_positions: [{play_positions_id: {id: "1"}}, {play_positions_id: {id: "2"}}]}) {
id
status
play_positions {
play_positions_id {
abbreviation
name
}
}
}
}
Output:
{
"data": {
"__typename": "Mutation",
"create_profiles_item": {
"id": "1337",
"status": "draft",
"play_positions": [
{
"play_positions_id": {
"id": "1",
"abbreviation": "RWB",
"name": "Right Wingback"
}
},
{
"play_positions_id": {
"id": "2",
"abbreviation": "CAM",
"name": "Central Attacking Midfielder"
}
}
],
}
}
}
由於您可以添加許多這些元素,因此我定義了一個變量/參數,如下所示
mutation CreateProfile2($cpppi: [create_profiles_play_positions_input]) {
__typename
create_profiles_item(data: {status: "draft", play_positions: $cpppi}) {
id
status
play_positions {
play_positions_id {
id
abbreviation
name
}
}
}
}
上面的變量 object:
"cpppi": {
"play_positions_id": {
"id": "1"
},
"play_positions_id": {
"id": "2
}
}
Output:
{
"data": {
"__typename": "Mutation",
"create_profiles_item": {
"id": "1338",
"play_positions": [
{
"play_positions_id": {
"id": "2",
"abbreviation": "CAM",
"name": "Central Attacking Midfielder"
}
}
],
}
}
}
架構:
input create_profiles_input {
id: ID
status: String!
play_positions: [create_profiles_play_positions_input]
}
input create_profiles_play_positions_input {
id: ID
play_positions_id: create_play_positions_input
}
input create_play_positions_input {
id: ID
abbreviation: String
name: String
}
在最后兩個片段中,只有最后一個 id 為“2”的 object 會發生變化。 我需要這些來使用后端定義的輸入類型。
我想到了。 我弄錯了變量中的括號。 這里的解決方案:
"cpppi": [
{
"play_positions_id": {
"id": "1"
}
},
{
"play_positions_id": {
"id": "2"
}
}
]
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.