參數類型&#39;Future<dynamic> 函數（字符串）”不能分配給參數類型“無效函數（字符串？）？”

Question

我正在使用顫振本地通知，但它不起作用，它突然使我的應用程序關閉。 這是我的代碼。

  initializeNotifications() async {
var initializationSettingsAndroid =
    AndroidInitializationSettings('@mipmap/launcher_icon');
var initializationSettingsIOS = IOSInitializationSettings();
var initializationSettings = InitializationSettings(
    android: initializationSettingsAndroid, iOS: initializationSettingsIOS);
var flutterLocalNotificationsPlugin;
await flutterLocalNotificationsPlugin.initialize(initializationSettings,
    onSelectNotification: onSelectNotification);

}

Future onSelectNotification(String payload) async {
if (payload != null) {
  debugPrint('notification payload: ' + payload);
}
await Navigator.push(
  context,
  new MaterialPageRoute(builder: (context) => MedicineReminder()),
);

}

Answer 1

await flutterLocalNotificationsPlugin.initialize(
  initializationSettings,
  onSelectNotification: (payload) {
    if (payload != null) {
      onSelectNotification(payload!);
    }
  }
);