參數類型 'Future<void> Function(String?)' 不能分配給參數類型 'void Function(NotificationResponse)？</void>

Question

我正在嘗試使用最新版本 flutter_local_notifications: ^13.0.0 在我的 Flutter 項目中包含本地通知，但出現此錯誤：

無法將參數類型“Future Function(String?)”分配給參數類型“void Function(NotificationResponse)”？

onDidReceiveNotificationResponse : onSelectNotification

這是我的課：

class LocalNotificationService {
  LocalNotificationService();

  final _localNotificationService = FlutterLocalNotificationsPlugin();

  final BehaviorSubject<String?> onNotificationClick = BehaviorSubject();

  Future<void> initialize() async {
    tz.initializeTimeZones();
    const AndroidInitializationSettings androidInitializationSettings =
        AndroidInitializationSettings('@drawable/ic_stat_android');

    DarwinInitializationSettings iosInitializationSettings =
    DarwinInitializationSettings(
      requestAlertPermission: true,
      requestBadgePermission: true,
      requestSoundPermission: true,
      onDidReceiveLocalNotification: onDidReceiveLocalNotification,
    );

    final InitializationSettings settings = InitializationSettings(
      android: androidInitializationSettings,
      iOS: iosInitializationSettings,
    );

    await _localNotificationService.initialize(
      settings,
      onDidReceiveNotificationResponse : onSelectNotification, //here is the error
    );
  }

  Future<NotificationDetails> _notificationDetails() async {
    const AndroidNotificationDetails androidNotificationDetails =
        AndroidNotificationDetails('channel_id', 'channel_name',
            channelDescription: 'description',
            importance: Importance.max,
            priority: Priority.max,
            playSound: true);

    const DarwinNotificationDetails iosNotificationDetails =
    DarwinNotificationDetails();

    return const NotificationDetails(
      android: androidNotificationDetails,
      iOS: iosNotificationDetails,
    );
  }

  Future<void> showNotification({
    required int id,
    required String title,
    required String body,
  }) async {
    final details = await _notificationDetails();
    await _localNotificationService.show(id, title, body, details);
  }

  Future<void> showScheduledNotification(
      {required int id,
      required String title,
      required String body,
      required int seconds}) async {
    final details = await _notificationDetails();
    await _localNotificationService.zonedSchedule(
      id,
      title,
      body,
      tz.TZDateTime.from(
        DateTime.now().add(Duration(seconds: seconds)),
        tz.local,
      ),
      details,
      androidAllowWhileIdle: true,
      uiLocalNotificationDateInterpretation:
          UILocalNotificationDateInterpretation.absoluteTime,
    );
  }

  Future<void> showNotificationWithPayload(
      {required int id,
      required String title,
      required String body,
      required String payload}) async {
    final details = await _notificationDetails();
    await _localNotificationService.show(id, title, body, details,
        payload: payload);
  }

  void onDidReceiveLocalNotification(
      int id, String? title, String? body, String? payload) {
    print('id $id');
  }

  Future<void> onSelectNotification(String? payload) async {
    print('payload $payload');
    if (payload != null && payload.isNotEmpty) {
      onNotificationClick.add(payload);
    }
  }
}

我缺少什么？

Answer 1

onDidReceiveNotificationResponse在回調時提供NotificationResponse 。 你可以獲得像這樣的payload

  onDidReceiveNotificationResponse: (details) =>
      onSelectNotification(details.payload),

要么

  Future<void> onSelectNotification(NotificationResponse? response) async {
    print('payload $response');
    if (response?.payload != null && response!.payload!.isNotEmpty) {
      onNotificationClick.add(response.payload);
    }
  }

這將用於onDidReceiveNotificationResponse: onSelectNotification 。