[英]Converting objects in file to json in python
我有一個包含多個對象的文件,如下所示:
{
name: (sindey, crosby)
game: "Hockey"
type: athlete
},
{
name: (wayne, gretzky)
game: "Ice Hockey"
type: athlete
}
...我想將它們轉換為 JSON 格式並輸出:
[
{
"name": "(sindey, crosby)",
"game": "Hockey",
"type": "athlete"
},
{
"name": "(wayne, gretzky)",
"game": "Ice Hockey",
"type": "athlete"
}
]
如果輸入是這種格式,
name: (sidney, crosby) | game:"Hockey" | type:athlete
name: (wayne, gretzky) | game:"Ice Hockey" | type:athlete
我可以使用帶有 list 和 dict 的 json dump 來實現,它給了我想要的輸出
import json
f = open("log.file", "r")
content = f.read()
splitcontent = content.splitlines()
d = []
for v in splitcontent:
l = v.split(' | ')
d.append(dict(s.split(':',1) for s in l))
with open("json_log.json", 'w') as file:
file.write((json.dumps(d, indent=4, sort_keys= False)))
如何重新格式化此代碼以將輸入轉換為 JSON 格式?
像這樣的東西可能適用於大多數情況 - 您只需將帶有花括號的行與帶有數據的行分開處理:
import json
f = open("log.file", "r")
content = f.read()
splitcontent = content.splitlines()
d = []
appendage = {}
for line in splitcontent:
if ('}' in line) or ('{' in line):
# Append a just-created record and start a new one
if appendage:
d.append(appendage)
appendage ={}
else:
key, val = line.split(':',1)
if val.endswith(','):
# strip a trailing comma
val = val[:-1]
appendage[key] = val
with open("json_log.json", 'w') as file:
file.write((json.dumps(d, indent=4, sort_keys= False)))
我可能也有一些錯別字...
@sarah Messer 給出的答案略有變化。 涉及的變化
沒有 : 分隔符的行被跳過
嘗試這個
import json
f = open("log.file", "r")
content = f.read()
splitcontent = content.splitlines()
d = []
appendage = {}
for line in splitcontent:
if ('}' in line) or ('{' in line) or ('{' in line) or ('}' in line):
# Append a just-created record and start a new one
if appendage:
d.append(appendage)
appendage = {}
continue
key, val = line.split(':')
if val.endswith(','):
# strip a trailing comma
val = val[:-1]
print(val)
# if val == "":
# pass
# else:
appendage[key] = val
with open("json_log.json", 'w') as file:
file.write((json.dumps(d, indent=4, sort_keys=False)))
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.