[英]how can i insert this data into this table from other tables?
表 XX_EMPLOYEES
CREATE TABLE XX_EMPLOYEES
( EMP_ID NUMBER NOT NULL, EMP_FIRST_NAME VARCHAR2(250) NOT NULL, EMP_MIDDLE_NAME VARCHAR2(250) NOT NULL, EMP_LAST_NAME VARCHAR2(250) NOT NULL, Hired_Date DATE NOT NULL, Country VARCHAR2(250) NOT NULL, Salary NUMBER NOT NULL );
INSERT ALL
INTO XX_EMPLOYEES (EMP_ID, EMP_FIRST_NAME, EMP_MIDDLE_NAME, EMP_LAST_NAME, Hired_Date, Country, Salary) VALUES (1,'Tomm','Jef','Adam','01-Jan-2016','JORDAN',1000) INTO XX_EMPLOYEES (EMP_ID, EMP_FIRST_NAME, EMP_MIDDLE_NAME, EMP_LAST_NAME, Hired_Date, Country, Salary) VALUES (2,'Mohammed','Ahmed','Mahmoud','15-Jul-2009','UAE',900) INTO XX_EMPLOYEES (EMP_ID, EMP_FIRST_NAME, EMP_MIDDLE_NAME, EMP_LAST_NAME, Hired_Date, Country, Salary) VALUES (4,'Ali','Ahmad','Mahmoud','07-Jul-2000','UK',1200) INTO XX_EMPLOYEES (EMP_ID, EMP_FIRST_NAME, EMP_MIDDLE_NAME, EMP_LAST_NAME, Hired_Date, Country, Salary) VALUES (10,'Basel','Jamal','Saeed','10-Apr-2001','UAE',1000)
SELECT * FROM dual;
表作業
CREATE TABLE Jobs
(
JOB_ID NUMBER NOT NULL,
JOB_Description VARCHAR2(250) NOT NULL
);
INSERT ALL
INTO Jobs (Job_ID, Job_Description) VALUES (1, 'Accountant')
INTO Jobs (Job_ID, Job_Description) VALUES (2, 'General Manager')
INTO Jobs (Job_ID, Job_Description) VALUES (3, 'Administration')
INTO Jobs (Job_ID, Job_Description) VALUES (4, 'Senior Accountant')
SELECT * FROM dual;
表職業
CREATE TABLE PROFESSION
( EMP_ID NUMBER NOT NULL,
JOB_ID NUMBER NOT NULL,
MANAGER_ID NUMBER,
EFFECTIVE_FROM DATE NOT NULL,
EFFECTIVE_TO DATE NOT NULL,
CONSTRAINT RESTRICT CHECK (EFFECTIVE_FROM < EFFECTIVE_TO)
)
現在如何使用所有 3 個表將此數據添加到專業表?
(Tomm, General Manager,null,01-Jan-2000,null)
(Mohammed, Senior Accountant, Tomm,01-Jan-2010, Null)
(Ali, Administration, Tomm,01-Jan-2000,Null)
(Basel, Accountant, Mohammed,01-Mar-2007,Null)
餐桌職業有以下限制:-
Staff、Effective_from 和 Effective_to 是必填字段,必須輸入。
Effective_from 必須小於 Effective_to。
對於同一員工,他在生效日內不得有兩條記錄。
試過這個,但仍然無法得到它
INSERT INTO PROFESSION(EMP_ID,JOB_ID,STAFF)
VALUES ((SELECT EMP_ID FROM XX_EMPLOYEES WHERE EMP_ID=1003),(SELECT JOB_ID FROM JOBS WHERE JOB_ID=102),(SELECT EMP_FIRST_NAME FROM XX_EMPLOYEES WHERE EMP_ID=1003))
要插入行,您必須通過case
表達式將xx_employees
和jobs
連接起來,從字面上將人員與工作連接起來。
SQL> INSERT INTO profession (emp_id,
2 job_id,
3 manager_id,
4 effective_from,
5 effective_to)
6 SELECT e.emp_id,
7 j.job_id,
8 --
9 CASE -- this CASE expression sets the manager
10 WHEN e.emp_id = 1 THEN NULL
11 WHEN e.emp_id = 2 THEN 1
12 WHEN e.emp_id = 4 THEN 1
13 WHEN e.emp_id = 10 THEN 2
14 END manager_id,
15 --
16 DATE '2000-01-01',
17 DATE '3000-01-01' -- the "TO" date can't be null, so it is set to far future
18 FROM xx_employees e
19 JOIN jobs j
20 ON j.job_id = -- CASE expressions says who does what
21 CASE
22 WHEN e.emp_id = 1 THEN 2
23 WHEN e.emp_id = 2 THEN 4
24 WHEN e.emp_id = 4 THEN 1
25 WHEN e.emp_id = 10 THEN 1
26 END;
4 rows created.
結果又是幾個表的連接; 請注意,您必須使用xx_employees
兩次: e
別名用於“員工”,而m
別名用於經理:
SQL> SELECT e.emp_first_name,
2 j.job_description,
3 m.emp_first_name manager,
4 p.effective_from,
5 p.effective_to
6 FROM profession p
7 JOIN xx_employees e ON e.emp_id = p.emp_id
8 LEFT JOIN xx_employees m ON m.emp_id = p.manager_id
9 JOIN jobs j ON j.job_id = p.job_id
10 ORDER BY p.emp_id;
EMP_FIRST_NAME JOB_DESCRIPTION MANAGER EFFECTIVE_F EFFECTIVE_T
--------------- -------------------- ---------- ----------- -----------
Tomm General Manager 01-jan-2000 01-jan-3000
Mohammed Senior Accountant Tomm 01-jan-2000 01-jan-3000
Ali Accountant Tomm 01-jan-2000 01-jan-3000
Basel Accountant Mohammed 01-jan-2000 01-jan-3000
SQL>
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