將 SQL 查詢轉換為 SEQUELIZE

Question

我正試圖圍繞創建這個續集查詢。

SELECT 
    dayofweek(datum) AS DOW, 
    concat(DAY(datum), '-', MONTH(datum)) AS datum, 
    ochtend, 
    middag, 
    avond 
FROM dbt.menus
    ORDER BY datum ASC LIMIT 5 OFFSET (variable in sequelize code);

我已經能夠創建 2 個單獨的查詢，其中“按過濾器排序”有效，“別名”有效，但未合並。

這就是我目前在續集中所擁有的

const amount = await Menu.count();
const listOfMenu = await Menu.findAll({ 
    order: [['datum', 'ASC']],
    offset: amount - 5,
    limit: 5,
    attributes: {
        include: [
            [
              Menu.sequelize.fn
              (
                "DATE_FORMAT", 
                Menu.sequelize.col("datum"), 
                "%d-%m "
              ),
              "datum",
            ],
          ]
     }
});

Answer 1

您只需要使用fn兩次： order和attributes選項：

const datumExpression = Menu.sequelize.fn
              (
                "DATE_FORMAT", 
                Menu.sequelize.col("datum"), 
                "%d-%m "
              )
const listOfMenu = await Menu.findAll({ 
    order: [[datumExpression, 'ASC']],
    offset: amount - 5,
    limit: 5,
    attributes: {
        include: [
            [
              datumExpression,
              "datum",
            ],
          ]
     }
});

您還可以將findAll和count查詢合並到一個findAndCountAll ，您將獲得帶有兩個 props 的結果： rows和count ：

const { rows: listOfMenu, count: amount } = await Menu.findAndCountAll({ 
    order: [[datumExpression, 'ASC']],
    offset: amount - 5,
    limit: 5,
    attributes: {
        include: [
            [
              datumExpression,
              "datum",
            ],
          ]
     }

});