排序原始查詢：有效的SQL查詢不返回任何內容

Question

我的sequelize查詢總是返回0個結果，但是當我將完全相同的查詢復制/粘貼到psql中時，它可以正常工作，並按預期返回正確的行

  return sequelize.query(
"SELECT * FROM orders" +
" INNER JOIN sizes ON orders.sizeid = sizes.sizeid" +
" INNER JOIN types ON sizes.typeid = types.typeid" +
" INNER JOIN items ON types.itemid = items.itemid" +
" WHERE orders.fbid = :fbid AND pickuptime >= :today" +
" ORDER BY orders.pickuptime ASC",
{ replacements: {fbid, today}, type: sequelize.QueryTypes.SELECT }

）;

fbid是一個整數，今天是一個字符串'yyyy-mm-dd'
如果放棄“今天”條件，我將返回行

是sequelize轉義我的日期字符串嗎？

Answer 1

如果您在SQL腳本中定義了類似fbid=:fbid命名參數，則應傳遞一個對象{fbid: 'fbid_value'} ，

還是如果您定義了未命名參數fbid=? ，則應傳遞一個數組['fbid_value'] 。

這是文檔http://docs.sequelizejs.com/en/latest/api/sequelize/#querysql-options-promise

嘗試將對象傳遞給替換對象：

return sequelize.query(
"SELECT * FROM orders" +
" INNER JOIN sizes ON orders.sizeid = sizes.sizeid" +
" INNER JOIN types ON sizes.typeid = types.typeid" +
" INNER JOIN items ON types.itemid = items.itemid" +
" WHERE orders.fbid = :fbid AND pickuptime >= :today" +
" ORDER BY orders.pickuptime ASC",
{ replacements: {fbid: 'fbid_value', today: 'today_value'}, type: sequelize.QueryTypes.SELECT }
);