排序原始查询：有效的SQL查询不返回任何内容

Question

我的sequelize查询总是返回0个结果，但是当我将完全相同的查询复制/粘贴到psql中时，它可以正常工作，并按预期返回正确的行

  return sequelize.query(
"SELECT * FROM orders" +
" INNER JOIN sizes ON orders.sizeid = sizes.sizeid" +
" INNER JOIN types ON sizes.typeid = types.typeid" +
" INNER JOIN items ON types.itemid = items.itemid" +
" WHERE orders.fbid = :fbid AND pickuptime >= :today" +
" ORDER BY orders.pickuptime ASC",
{ replacements: {fbid, today}, type: sequelize.QueryTypes.SELECT }

）;

fbid是一个整数，今天是一个字符串'yyyy-mm-dd'
如果放弃“今天”条件，我将返回行

是sequelize转义我的日期字符串吗？

Answer 1

如果您在SQL脚本中定义了类似fbid=:fbid命名参数，则应传递一个对象{fbid: 'fbid_value'} ，

还是如果您定义了未命名参数fbid=? ，则应传递一个数组['fbid_value'] 。

这是文档http://docs.sequelizejs.com/en/latest/api/sequelize/#querysql-options-promise

尝试将对象传递给替换对象：

return sequelize.query(
"SELECT * FROM orders" +
" INNER JOIN sizes ON orders.sizeid = sizes.sizeid" +
" INNER JOIN types ON sizes.typeid = types.typeid" +
" INNER JOIN items ON types.itemid = items.itemid" +
" WHERE orders.fbid = :fbid AND pickuptime >= :today" +
" ORDER BY orders.pickuptime ASC",
{ replacements: {fbid: 'fbid_value', today: 'today_value'}, type: sequelize.QueryTypes.SELECT }
);