這個用於提醒通知的 python 程序使計算機變慢，這里的代碼有什么問題？ 我已經完成 pip 安裝 plyer

Question

我是 python 編程的新手，並試圖使這個程序工作，它應該作為飲用水 windows 通知提醒。

# importing python’s standard time utility module
import time

from plyer import notification

if __name__ == '__main__':
    while True:
        notification.notify(
            title = "**Please Drink Water Now!!",
            message ="The National Academies of Sciences, Engineering, and Medicine determined that an adequate daily fluid intake is: About 15.5 cups (3.7 liters) of fluids for men. About 11.5 cups (2.7 liters) of fluids a day for women.",
            app_icon = "C:/Users/swast/OneDrive/Desktop/pythProject/media/icon.png",
            timeout= 12
            )

time.sleep(6)

每當我嘗試運行此程序時，我的計算機由於某種原因變慢，並且終端旁邊的 output 選項卡一直在運行，而沒有通知，我在這里做錯了什么？

Answer 1

這是建議的代碼的修補程序：

# importing python’s standard time utility module
import time

from plyer import notification

if __name__ == '__main__':
    while True:
        notification.notify(
            title = "**Please Drink Water Now!!",
            message ="The National Academies of Sciences, Engineering, and Medicine determined that an adequate daily fluid intake is: About 15.5 cups (3.7 liters) of fluids for men. About 11.5 cups (2.7 liters) of fluids a day for women.",
            app_icon = "C:/Users/swast/OneDrive/Desktop/pythProject/media/icon.png",
            timeout= 12
            )

        time.sleep(6)

執行此操作的正確方法是使用 crontab 在所需時間調用腳本。 該腳本只會調用一次notification.notify 。