隨機化列表並將結果導出為唯一的 4 個字符串集

Question

我想隨機化字符串列表，9 個不同的字符串，然后將字符串打印成唯一的一組四個，然后將其導出到 txt 文件中。 到目前為止，這是我嘗試過的，但我不確定如何將它們分成四組。

import random
a = "0xa5"
b = "0x1"
c = "0xE5924"
d = "0xE59"
e = "0xC60aE"
g = "0xd7F1DF"
h = "0xDEF1717"
i = "0xA102072A4C07F9"
j = "0x934A0E2c6C427D9F25"



my_list = [a,b,c,d,e,g,h,i,j]
random.shuffle(my_list)
myset = set(my_list)
print(myset)

我希望打印結果出現在以下示例中：

["0xa5","0x1","0xE5924","0xE59"],
["0xa5","0x1","0xE5924","0xA102072A4C07F9"],

Answer 1

import random
a = "0xa5"
b = "0x1"
c = "0xE5924"
d = "0xE59"
e = "0xC60aE"
g = "0xd7F1DF"
h = "0xDEF1717"
i = "0xA102072A4C07F9"
j = "0x934A0E2c6C427D9F25"
print(list(set(random.sample([a,b,c,d,e,g,h,i,j],4))))

Answer 2

我用一個while循環來做，只是選擇你得到的集合的隨機數。

oldarray= my_list
newarray=[]
count=0
while count<4:
    num=random.randint(0,8)
    newarray.append(oldarray[num])
    count+=1
print(newarray)