随机化列表并将结果导出为唯一的 4 个字符串集

Question

我想随机化字符串列表，9 个不同的字符串，然后将字符串打印成唯一的一组四个，然后将其导出到 txt 文件中。 到目前为止，这是我尝试过的，但我不确定如何将它们分成四组。

import random
a = "0xa5"
b = "0x1"
c = "0xE5924"
d = "0xE59"
e = "0xC60aE"
g = "0xd7F1DF"
h = "0xDEF1717"
i = "0xA102072A4C07F9"
j = "0x934A0E2c6C427D9F25"



my_list = [a,b,c,d,e,g,h,i,j]
random.shuffle(my_list)
myset = set(my_list)
print(myset)

我希望打印结果出现在以下示例中：

["0xa5","0x1","0xE5924","0xE59"],
["0xa5","0x1","0xE5924","0xA102072A4C07F9"],

Answer 1

import random
a = "0xa5"
b = "0x1"
c = "0xE5924"
d = "0xE59"
e = "0xC60aE"
g = "0xd7F1DF"
h = "0xDEF1717"
i = "0xA102072A4C07F9"
j = "0x934A0E2c6C427D9F25"
print(list(set(random.sample([a,b,c,d,e,g,h,i,j],4))))

Answer 2

我用一个while循环来做，只是选择你得到的集合的随机数。

oldarray= my_list
newarray=[]
count=0
while count<4:
    num=random.randint(0,8)
    newarray.append(oldarray[num])
    count+=1
print(newarray)