乒乓球游戲中的球不擊球

Question

並不是說它不起作用，而是它真的很受歡迎。 查找球是否在槳 x 內的代碼可以完美運行，但 y 不能。 我認為它與槳或球的邊緣有關，它從槳區域外進入槳，但請幫忙，或者至少不要對我大喊大叫，說我愚蠢，謝謝！

import pygame,sys,time,random

pygame.init()
width,height =1000,600
win = pygame.display.set_mode((width,height))
pygame.display.set_caption("Hello World")

p1 = 40
p1width = 100
p1score = 0

p2 = 560
p2width = 100
p2score = 0

speed = 4

ballvx=random.randint(1,2)
ballvy=random.randint(1,2)

ballx=300
bally=50

font = pygame.font.Font('CursedTimerUlil-Aznm.ttf', 100)
p1text = font.render(str(p1score), True,(255,255,255))
p1textRect = p1text.get_rect()
p1textRect.center = (width/2/2, 250)

p2text = font.render(str(p1score), True,(255,255,255))
p2textRect = p2text.get_rect()
p2textRect.center = (width/2+(width/2/2), 250)

while True:
    win.fill((0,0,0))
    #line
    pygame.draw.rect(win, (40,40,40), pygame.Rect(width/2-2, 0, 4, 600))
    
    #p1
    pygame.draw.rect(win, (255,255,255), pygame.Rect(p1, 550, p1width, 10))

    #p2
    pygame.draw.rect(win, (255,255,255), pygame.Rect(p2, 550, p2width, 10))

    #ball
    pygame.draw.rect(win, (255,255,255), pygame.Rect(ballx, bally, 20, 20))    

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            sys.exit()

    keys = pygame.key.get_pressed()
    if keys[pygame.K_a]  and p1-speed>=0:
        p1-=speed
    if keys[pygame.K_d]  and p1+speed<=width/2-p1width-2:
        p1+=speed
    if keys[pygame.K_LEFT]  and p2-speed>=width/2+2:
        p2-=speed
    if keys[pygame.K_RIGHT]  and p2+speed<=width-p2width:
        p2+=speed
        
    ballx+=ballvx
    bally+=ballvy
    
    if ballx+ballvx>=width-20:
        ballvx*= -1
        ballx+=0.1
        bally+=0.1
        
        
    if ballx+ballvx<=0:
        ballvx *= -1
        ballx+=0.1
        bally+=0.1
    if bally+ballvy>=height-20:
        print(width/2)
        print(ballx)
        if ballx <= width/2:
            
            p2score+=1
            print("score")
        else:
            p1score+=1
            print("is this even running???") 

        bally = 50
        ballx = random.randint(200,800)
        ballvx=random.randint(1,2)
        ballvy=random.randint(1,2)
        

    if bally+ballvy<=0:
        ballx+=0.1
        ballvy*=-1
        bally+=0.1
    
    if ballx+ballvx in range(p1,p1+p1width) and  bally+20 + ballvy >=550 :
        ballvy*=-1
        ballx+=0.1
        bally+=0.1
    if ballx+ballvx in range(p2,p2+p2width) and  bally+20 + ballvy >=550:
        ballvy*=-1
        ballx+=0.1
        bally+=0.1


    time.sleep(0.01)
    
    p1text = font.render(str(p1score), True,(255,255,255))
    p1textRect = p1text.get_rect()
    p1textRect.center = (width/2/2, 250)
    win.blit(p1text, p1textRect)

    p2text = font.render(str(p2score), True,(255,255,255))
    p2textRect = p2text.get_rect()
    p2textRect.center = (width/2+(width/2/2), 250)
    win.blit(p2text,p2textRect)


    pygame.display.update()

Answer 1

ballx+ballvx in range(p1,p1+p1width)不符合您的預期。 range function 產生一個整數值序列。 因此， x in range(a, b)檢查x是否恰好是范圍[a, b)中的整數之一。 如果x是浮點數，則它不是范圍內的 integer。

例如： range(5, 8)生成序列5, 6, 7 。 整數6在這個序列中。 但是，浮點數6.5不在此序列中。

如果要檢查浮點數x是否在[a, b]范圍內，則必須使用比較運算符（例如a <= x <= b ）：

while True:
    # [...]

    if p1 <= ballx+ballvx <= p1+p1width and bally+20 + ballvy >=550:
        ballvy*=-1
        ballx+=0.1
        bally+=0.1
    if p2 <= ballx+ballvx <= p2+p2width and  bally+20 + ballvy >=550:
        ballvy*=-1
        ballx+=0.1
        bally+=0.1