[英]Python if elif and else statement not working
我正在嘗試編寫一個簡短的腳本來娛樂自己和潛在的其他人。 當我運行它時,它往往會跳過 if elif 和 else 語句。
import random
adventure = ["fantasy" , "sci-fi" , "pirate" , "pre-history"]
setting = ["ocean", "forest" , "desert" , "castle"]
while True:
adven = []
setti = []
random.shuffle(adventure)
random.shuffle(setting)
adven.append(adventure[0])
setti.append(setting[0])
print(adven)
print(setti)
accept = input("Is this acceptable? ")
if accept == "y" :
print("Great, let us get started!")
break
else :
print("I am so sorry, lets try again!")
adve = []
sett = []
adve.append(adven)
sett.append(setti)
if adve == "fantasy" :
if sett == "ocean" :
print("1")
elif sett == "forest" :
print("2")
elif sett == "desert" :
print("3")
elif sett == "castle" :
print("4")
if adve == "sci-fi" :
if sett == "ocean" :
print("5")
elif sett == "forest" :
print("6")
elif sett == "desert" :
print("7")
elif sett == "castle" :
print("8")
if adve == "pirate" :
if sett == "ocean" :
print("9")
elif sett == "forest" :
print("10")
elif sett == "desert" :
print("11")
elif sett == "castle" :
print("12")
if adve == "pre-history" :
if sett == "ocean" :
print("13")
elif sett == "forest" :
print("14")
elif sett == "desert" :
print("15")
elif sett == "castle" :
print("16")
print(adve)
print(sett)
我需要將它保存在 while True 循環中嗎? 我不確定該怎么做,因為我想在我將任何真實的細節寫入腳本之前確保它能夠正常工作。
試試看in
如:
if "fantasy" in advve:
可能比==
這里更適合你。
為什么? 因為您正在測試字符串是否在字符串列表中。
不要忘記交換你的操作數。 不像==
in
cares 是第一位的。
據我了解,您希望在adven
和setti
中有多個值,這就是為什么它是一個列表?
因此,首先,您應該在循環 scope 之外定義這些值:
adven = []
setti = []
while True:
...
您將列表附加到列表中,因此您在列表中獲得列表。
adve = []
adve.append(["random", "stuff"])
print(adve)
# [['random', 'stuff']]
將列表與字符串進行比較總是錯誤的,因為您比較的是不同類型的值。
print(adve == "random")
# False
print(["random"] == "random")
# False
要修復它,您應該:
# adve.append(adven)
adve = adven.copy() # or simply `adve = adven`, or just use adven instead adve.
print(adve)
# ['random', 'stuff']
和:
# adve == "random"
print("random" in adve)
# True
順便說一句,你應該使用pop() function 所以你不會得到重復:
# adven.append(adventure[0])
# setti.append(setting[0])
adven.append(adventure.pop())
setti.append(setting.pop())
如果我誤解了,並且您不需要處理adven
和setti
的多個值,那么您的代碼應該如下所示:
import random
adventure = ["fantasy", "sci-fi", "pirate", "pre-history"]
setting = ["ocean", "forest", "desert", "castle"]
while True:
random.shuffle(adventure)
random.shuffle(setting)
adven = adventure[0]
setti = setting[0]
print(adven)
print(setti)
accept = input("Is this acceptable? ")
if accept == "y":
print("Great, let us get started!")
break
else:
print("I am so sorry, lets try again!")
adve = adven
sett = setti
multiplier = 0
if adve == "fantasy":
multiplier = 1
elif adve == "sci-fi":
multiplier = 2
elif adve == "pirate":
multiplier = 3
elif adve == "pre-history":
multiplier = 4
else:
print(f"issue with adve: {adve}")
if sett == "ocean":
print(multiplier * 1)
elif sett == "forest":
print(multiplier * 2)
elif sett == "desert":
print(multiplier * 3)
elif sett == "castle":
print(multiplier * 4)
print(adve)
print(sett)
還有一件事是錯誤的,如果你想提高你的編碼基礎,你只是沒有把 else 語句放在 elif 語句之后。 我建議您通過觀看像您這樣的項目來完成您的項目。
例如,您需要像這樣添加這個“else”語句:
if adve == "fantasy" :
if sett == "ocean" :
print("1")
elif sett == "forest" :
print("2")
elif sett == "desert" :
print("3")
elif sett == "castle" :
print("4")
else :
print("I am so sorry, you picked a wrong choice")
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