Python 如果 elif 和 else 语句不起作用

Question

我正在尝试编写一个简短的脚本来娱乐自己和潜在的其他人。 当我运行它时，它往往会跳过 if elif 和 else 语句。

import random

adventure = ["fantasy" , "sci-fi" , "pirate" , "pre-history"]
setting = ["ocean", "forest" , "desert" , "castle"]
while True:

    adven = []
    setti = []
    random.shuffle(adventure)
    random.shuffle(setting)
    adven.append(adventure[0])
    setti.append(setting[0])
    print(adven)
    print(setti)
    accept = input("Is this acceptable? ")
    if accept == "y" :
        print("Great, let us get started!")
        break
    else :
        print("I am so sorry, lets try again!")
adve = []
sett = []
adve.append(adven)
sett.append(setti)

if adve == "fantasy" :
    if sett == "ocean" :
        print("1")
    elif sett == "forest" :
        print("2")
    elif sett == "desert" :
        print("3")
    elif sett == "castle" :
        print("4")
if adve == "sci-fi" :
    if sett == "ocean" :
        print("5")
    elif sett == "forest" :
        print("6")
    elif sett == "desert" :
        print("7")
    elif sett == "castle" :
        print("8")
if adve == "pirate" :
    if sett == "ocean" :
        print("9")
    elif sett == "forest" :
        print("10")
    elif sett == "desert" :
        print("11")
    elif sett == "castle" :
        print("12")
if adve == "pre-history" :
    if sett == "ocean" :
        print("13")
    elif sett == "forest" :
        print("14")
    elif sett == "desert" :
        print("15")
    elif sett == "castle" :
        print("16")

print(adve)
print(sett)

我需要将它保存在 while True 循环中吗？ 我不确定该怎么做，因为我想在我将任何真实的细节写入脚本之前确保它能够正常工作。

Answer 1

试试看in 如：

if "fantasy" in advve:

可能比==这里更适合你。

为什么？ 因为您正在测试字符串是否在字符串列表中。

_{不要忘记交换你的操作数。 不像== in cares 是第一位的。}

Answer 2

据我了解，您希望在adven和setti中有多个值，这就是为什么它是一个列表？

因此，首先，您应该在循环 scope 之外定义这些值：

adven = []
setti = []
while True:
    ...

---

您将列表附加到列表中，因此您在列表中获得列表。

adve = []
adve.append(["random", "stuff"])
print(adve)
# [['random', 'stuff']]

将列表与字符串进行比较总是错误的，因为您比较的是不同类型的值。

print(adve == "random")
# False
print(["random"] == "random")
# False

要修复它，您应该：

# adve.append(adven)
adve = adven.copy()  # or simply `adve = adven`, or just use adven instead adve.
print(adve)
# ['random', 'stuff']

和：

# adve == "random"
print("random" in adve)
# True

---

顺便说一句，你应该使用pop() function 所以你不会得到重复：

# adven.append(adventure[0])
# setti.append(setting[0])
adven.append(adventure.pop())
setti.append(setting.pop())

---

如果我误解了，并且您不需要处理adven和setti的多个值，那么您的代码应该如下所示：

import random

adventure = ["fantasy", "sci-fi", "pirate", "pre-history"]
setting = ["ocean", "forest", "desert", "castle"]
while True:
    random.shuffle(adventure)
    random.shuffle(setting)
    adven = adventure[0]
    setti = setting[0]
    print(adven)
    print(setti)
    accept = input("Is this acceptable? ")
    if accept == "y":
        print("Great, let us get started!")
        break
    else:
        print("I am so sorry, lets try again!")
adve = adven
sett = setti


multiplier = 0
if adve == "fantasy":
    multiplier = 1
elif adve == "sci-fi":
    multiplier = 2
elif adve == "pirate":
    multiplier = 3
elif adve == "pre-history":
    multiplier = 4
else:
    print(f"issue with adve: {adve}")

if sett == "ocean":
    print(multiplier * 1)
elif sett == "forest":
    print(multiplier * 2)
elif sett == "desert":
    print(multiplier * 3)
elif sett == "castle":
    print(multiplier * 4)

print(adve)
print(sett)

Answer 3

还有一件事是错误的，如果你想提高你的编码基础，你只是没有把 else 语句放在 elif 语句之后。 我建议您通过观看像您这样的项目来完成您的项目。

例如，您需要像这样添加这个“else”语句：

if adve == "fantasy" :
    if sett == "ocean" :
        print("1")
    elif sett == "forest" :
        print("2")
    elif sett == "desert" :
        print("3")
    elif sett == "castle" :
        print("4")
    else :
        print("I am so sorry, you picked a wrong choice")