[英]Solved | Python: If/elif/else Statement Not Working as Expected?
[英]Python - if, elif, elif, else Statement Not Working as Expected
我正在将Django用于网站,并且需要构建上下文处理器来提供引荐来源(变量为referer
)信息。
我有一个简单的if,elif,elif,else语句:
[ . . . ]
host = get_current_site(request)
local_url = SITE_URLS['local']
dev_url = SITE_URLS['dev']
prod_url = SITE_URLS['prod']
# print referer for debugging purposes - remove when done...
print("current host: {0}".format(host))
print("current urls: {0} {1} {2}".format(local_url, dev_url, prod_url))
# determine default referer - eg, set as host/site name
if host == prod_url:
referer = prod_url
elif host == dev_url:
referer = dev_url
elif host == local_url:
referer = local_url
else:
# set referer for current request
try:
referer = request.META['HTTP_REFERER']
except KeyError as e:
print('ERROR: key error - referer doesn\'t exist: {0}'.format(str(e)));
[ . . . ]
奇怪的是,上面的打印语句产生的host
等于local_url
(从控制台):
current host: http://localhost:8000
current urls: http://localhost:8000 [ . . . ]
但是它仍在评估else>尝试并抛出关键错误...重点是,仅当默认主机/站点不可用时, request.META['HTTP_REFERER']
有效。
这是怎么了? 我想念一些东西。 Python告诉我host != local_url
但是为什么呢?
编辑
感谢@Martijn Pieters的一个很好的提示。 我更改了打印语句,现在看到了:
current host: <Site: http://localhost:8000>
current urls: 'http://localhost:8000'
我想我忘了使用网站框架的属性:
您很可能遇到空白问题; 将格式替换为:
print("current host: {0!r}".format(host))
print("current urls: {0!r} {1!r} {2!r}".format(local_url, dev_url, prod_url))
改用repr()
值; 这些将包含有关值类型的更多信息,任何尾随空格将立即显而易见。
如果看到django.contrib.sites.models.Site
对象,请与domain
属性进行比较:
if host.domain == prod_url:
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