如何按日期總結兩個不同的嵌套列表（Mongodb聚合）

Question

我有一個對象列表，每個對象都有兩個列表，如下所示：

[
  {
    "name": "market2",
    "materialCosts": [
      {
        "date": "2022-02-12",
        "amount": "1234.11"
      },
      {
        "date": "2022-02-15",
        "amount": "1234.11"
      }
    ],
    "laborCosts": [
      {
        "date": "2022-02-12",
        "amount": "12.11"
      },
      {
        "date": "2022-02-15",
        "amount": "45.11"
      }
    ]
  },
  {
    "name": "market1",
    "materialCosts": [
      {
        "date": "2022-02-12",
        "amount": "1234.11"
      },
      {
        "date": "2022-02-15",
        "amount": "1234.11"
      }
    ],
    "laborCosts": [
      {
        "date": "2022-02-12",
        "amount": "12.11"
      },
      {
        "date": "2022-02-15",
        "amount": "45.11"
      }
    ]
  }
]

是否有可能使用 mongodb 聚合框架按日期對所有成本進行分組，無論它們是材料成本還是人工成本，最終得到以下結果：

[
  {
    "date": "2022-02-12",
    "amount": "1234.11"
  },
  {
    "date": "2022-02-15",
    "amount": "1234.11"
  }
]

Answer 1

詢問

• 連接兩個 arrays
• 放松
• 按日期和總和分組

玩蒙哥

aggregate(
[{"$project": 
   {"costs": {"$concatArrays": ["$materialCosts", "$laborCosts"]}}},
 {"$unwind": "$costs"},
 {"$group": 
   {"_id": "$costs.date", "sum": {"$sum": {"$toDouble": "$costs.amount"}}}}])