如何按日期总结两个不同的嵌套列表（Mongodb聚合）

Question

我有一个对象列表，每个对象都有两个列表，如下所示：

[
  {
    "name": "market2",
    "materialCosts": [
      {
        "date": "2022-02-12",
        "amount": "1234.11"
      },
      {
        "date": "2022-02-15",
        "amount": "1234.11"
      }
    ],
    "laborCosts": [
      {
        "date": "2022-02-12",
        "amount": "12.11"
      },
      {
        "date": "2022-02-15",
        "amount": "45.11"
      }
    ]
  },
  {
    "name": "market1",
    "materialCosts": [
      {
        "date": "2022-02-12",
        "amount": "1234.11"
      },
      {
        "date": "2022-02-15",
        "amount": "1234.11"
      }
    ],
    "laborCosts": [
      {
        "date": "2022-02-12",
        "amount": "12.11"
      },
      {
        "date": "2022-02-15",
        "amount": "45.11"
      }
    ]
  }
]

是否有可能使用 mongodb 聚合框架按日期对所有成本进行分组，无论它们是材料成本还是人工成本，最终得到以下结果：

[
  {
    "date": "2022-02-12",
    "amount": "1234.11"
  },
  {
    "date": "2022-02-15",
    "amount": "1234.11"
  }
]

Answer 1

询问

• 连接两个 arrays
• 放松
• 按日期和总和分组

玩蒙哥

aggregate(
[{"$project": 
   {"costs": {"$concatArrays": ["$materialCosts", "$laborCosts"]}}},
 {"$unwind": "$costs"},
 {"$group": 
   {"_id": "$costs.date", "sum": {"$sum": {"$toDouble": "$costs.amount"}}}}])