smtlib 不從 pandas Z6A8064B5DF347945057055 的列列表中將 email 發送到 email 地址

Question

親愛的

我有一個代碼連接到 Oracle DB，以 Daraframe 的形式獲取查詢並將 email 發送到列中存在的接收器

當我測試時，當我將 test_reciver 參數設置為 email 地址 test_reciver Email 收到但當我將（電子郵件接收者）設置為數據幀列時，沒有收到 Email

#send mail function
def send_email(subject,to,cc,body):
    sender_email = 'test@test.com'
    receivers = to
    host = "bulkmail.test.com"
    server = smtplib.SMTP(host)
    msg = MIMEText(body)
    msg['Subject'] = subject
    msg['to'] = to
    msg['cc'] = cc
    server.sendmail(sender_email,to,msg.as_string())
    server.quit()


query = "select * from sometable"
test_reciver = "myemail@test.com"

con = cx_Oracle.connect(user_db,password_db,dsn_tns,encoding="UTF-8", nencoding="UTF-8")
cc = 'emailcctest@test.com'
df = pd.read_sql_query(query,con, index_col=None).head(1)
df = df.reset_index()
for index, row in df.iterrows():
    print(row['EMAIL'])
    subject = 'please clarify your Workgroup in SDM '
    to = row['EMAIL']
    body = 'sample body'
    send_email(subject, to, cc, body)

con.close()

Answer 1

它通過發送 email 作為 object 與 send_message 而不是 sendmail 為 smtplib 解決

#send mail function
def send_email(subject,to,cc,body):
    host = "bulkmail.test.com"
    server = smtplib.SMTP(host)
    msg = MIMEText(body)
    msg['Subject'] = subject
    msg['From'] = 'test@test.com'
    msg['to'] = to
    msg['cc'] = email_cc
    serve.send_message(msg)
    server.quit()