[英]Python: Reshape a list of tuples into an aggregated list of dictionaries
我有一些data
包含在 Python 的元組列表中,如下所示。
data = [('Test-1', 1, 0.203194), ('Test-1', 2, 0.0143804), ('Test-1', 3, 0.0769853), ('Test-2', 1, 0.00173769), ('Test-3', 1, 0.00842112), ('Test-3', 2, 0.128969), ('Test-4', 1, 0.0481806)]
每個元組包含一個值test_name
、 session
數字和percentile
分數(按確切順序)。 我需要將這些data
重塑為一個字典列表,其中每個唯一的test_name
都按如下方式分組:
[
{
"test_name": "Test-1",
"session": [
{"submission": 1, "percentile": 0.203194},
{"submission": 2, "percentile": 0.0143804},
{"submission": 3, "percentile": 0.0769853}
]
},
{
"test_name": "Test-2",
"session": [
{"submission": 1, "percentile": 0.0}
]
},
{
"test_name": "Test-3",
"session": [
{"submission": 1, "percentile": 0.0},
{"submission": 2, "percentile": 0.0}
]
},
{
"test_name": "Test-4",
"session": [
{"submission": 1, "percentile": 0.0}
]
}
]
我怎么能在 Python 中做到這一點?
這里我假設data
中相同的test_name
是連續的,這樣我就可以寫成一行:
>>> from itertools import groupby
>>> from operator import itemgetter
>>> [{'test_name': test_name,
... 'session': [{'submission': submission, 'percentile': percentile}
... for _, submission, percentile in group]}
... for test_name, group in groupby(data, key=itemgetter(0))]
[{'test_name': 'Test-1',
'session': [{'submission': 1, 'percentile': 0.203194},
{'submission': 2, 'percentile': 0.0143804},
{'submission': 3, 'percentile': 0.0769853}]},
{'test_name': 'Test-2',
'session': [{'submission': 1, 'percentile': 0.00173769}]},
{'test_name': 'Test-3',
'session': [{'submission': 1, 'percentile': 0.00842112},
{'submission': 2, 'percentile': 0.128969}]},
{'test_name': 'Test-4',
'session': [{'submission': 1, 'percentile': 0.0481806}]}]
如果假設不成立:
>>> mp = {}
>>> for test_name, submission, percentile in data:
... mp.setdefault(test_name, []).append({'submission': submission, 'percentile': percentile})
...
>>> [{'test_name': test_name, 'session': session}
... for test_name, session in mp.items()]
[{'test_name': 'Test-1',
'session': [{'submission': 1, 'percentile': 0.203194},
{'submission': 2, 'percentile': 0.0143804},
{'submission': 3, 'percentile': 0.0769853}]},
{'test_name': 'Test-2',
'session': [{'submission': 1, 'percentile': 0.00173769}]},
{'test_name': 'Test-3',
'session': [{'submission': 1, 'percentile': 0.00842112},
{'submission': 2, 'percentile': 0.128969}]},
{'test_name': 'Test-4',
'session': [{'submission': 1, 'percentile': 0.0481806}]}]
讓我們將問題分解為步驟
這就是我使用簡單原語(循環、列表、字典)的方式
intermediate_dict = {} # dictionaries of dictionaries
# 1. For each tuple identify the "key"
for tup in data:
key, submission, percentile = tup
if key in intermediate_dict:
# 3. If you have seen the key before, update the dictionary
intermediate_dict[key]["session"].append({"submission": submission, "percentile": percentile})
else:
# 2. Prepare a dictonary for a key that you haven't seen before
intermediate_dict[key] = {"session": [{"submission": submission, "percentile": percentile}]}
您的中間字典可能看起來像這樣
{'Test-1': {'session': [{'submission': 1, 'percentile': 0.203194},
{'submission': 1, 'percentile': 0.203194},
{'submission': 2, 'percentile': 0.0143804},
{'submission': 3, 'percentile': 0.0769853}]},
'Test-2': {'session': [{'submission': 1, 'percentile': 0.00173769}]},
'Test-3': {'session': [{'submission': 1, 'percentile': 0.00842112},
{'submission': 2, 'percentile': 0.128969}]},
'Test-4': {'session': [{'submission': 1, 'percentile': 0.0481806}]}}
現在下一步是簡單地將字典轉換為列表
return [{"test_name": key, "session": value["session"]} for key, value in intermediate_dict.items()]
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