[英]How to return the row index of each element from a 2D array?
我有一個 8x10 二維數組 A。我需要另一個只存儲 A 的每個元素的行索引的二維數組。我 go 如何這樣做？ 感謝你的幫助！
我想我明白了！
C = np.array(np.where(A))[0].reshape(10, 8)
如何使用二維數組每一行的元素壓縮一維數組中的每個元素？
[英]How to zip each element from a 1D array with the elements from each row of a 2D array?
從1D重塑為2D numpy數組后，如何返回元素的位置（索引）？
[英]How to return the position (Index) of an element after reshaping from 1D to 2D numpy array?
Python with numpy：如何根據特定索引從二維數組的每一行中刪除一個元素
[英]Python with numpy: How to delete an element from each row of a 2-D array according to a specific index
對於2d numpy數組的每一行，在第二個2d數組中獲取相等行的索引
[英]For each row of a 2d numpy array get the index of an equal row in a second 2d array
如何通過另一個 2d 索引數組對 2d numpy-array 的每一行進行排序？
[英]How can I sort each row of the 2d numpy-array by another 2d index-array?
如何在不使用嵌套 for 循環的情況下根據其索引值划分 2d numpy 數組中的每個元素？
[英]How to divide each element in a 2d numpy array in relation to its index value without the use of nested for loops?
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