Javascript組將object數組嵌套到另一個數組中

Question

我有一個數組用於跟蹤某些文檔的狀態。 從 Mongo 聚合 function 輸出時，這看起來像以下內容k是狀態， v是具有此狀態的文檔數。

[
    {
        "legal": [
            { "k": "", "v": 6 },
            { "v": 3},
            { "k": "To be uploaded", "v": 5 },
            { "k": "To be reviewed", "v": 96 }
        ],
        "operations": [
            { "v": 1 },
            { "k": "To be uploaded", "v": 3 },
            { "k": "To be reviewed", "v": 24 }
        ],
        "accounting": [
            { "k": "To be reviewed", "v": 137 },
            { "k": "", "v": 3 },
            { "v": 2 },
            { "k": "To be uploaded", "v": 24 },
            { "k": "Not Required", "v": 1 }
        ]
    }
]

我想在堆疊條形圖上繪制這些圖形，並需要以下格式。 數據數組的順序是 ["legal", "operations", "accounting"]

 [
    {
      name: "",  // no status specified
      data: [9, 1, 5]
    },
    {
      name: "To be uploaded",
      data: [5, 3, 24]
    },
    {
      name: "To be reviewed",
      data: [96, 24, 137]
    },
    {
      name: "Not Required",
      data: [0, 0, 1]
    },
  ]

Answer 1

一種方法是結合使用Array#map和Array#reduce方法，如下所示。 Array#reduce非常適合創建數據摘要和清理數據 object，而Array#map有助於最終呈現。 當然，它可以改進：

 const input = [ { "legal": [ { "k": "", "v": 6 }, { "v": 3}, { "k": "To be uploaded", "v": 5 }, { "k": "To be reviewed", "v": 96 } ], "operations": [ { "v": 1 }, { "k": "To be uploaded", "v": 3 }, { "k": "To be reviewed", "v": 24 } ], "accounting": [ { "k": "To be reviewed", "v": 137 }, { "k": "", "v": 3 }, { "v": 2 }, { "k": "To be uploaded", "v": 24 }, { "k": "Not Required", "v": 1 } ] } ], summary = input.map( ({legal,operations,accounting}) => ({ legal:legal.reduce((acc,{k,v}) => ({...acc,[k || "NONE"]:(acc[k || "NONE"] || 0) + v}),{"Not Required":0}), operations:operations.reduce((acc,{k,v}) => ({...acc,[k || "NONE"]:(acc[k || "NONE"] || 0) + v}),{"Not Required":0}), accounting:accounting.reduce((acc,{k,v}) => ({...acc,[k || "NONE"]:(acc[k || "NONE"] || 0) + v}),{"Not Required":0}) }) ), output = summary.flatMap( o => Object.keys(Object.values(o)[0]).map( z => ({ name: z === "NONE"? "": z, data: Object.keys(o).map(y => o[y][z]) }) ) ); console.log( output );

或者.....

您可以按如下方式動態創建summary ：

 const input = [ { "legal": [ { "k": "", "v": 6 }, { "v": 3}, { "k": "To be uploaded", "v": 5 }, { "k": "To be reviewed", "v": 96 } ], "operations": [ { "v": 1 }, { "k": "To be uploaded", "v": 3 }, { "k": "To be reviewed", "v": 24 } ], "accounting": [ { "k": "To be reviewed", "v": 137 }, { "k": "", "v": 3 }, { "v": 2 }, { "k": "To be uploaded", "v": 24 }, { "k": "Not Required", "v": 1 } ] } ], summary = input.flatMap( o => Object.keys(o).reduce( (ac,cat) => ({...ac, [cat]:o[cat].reduce((acc,{k,v}) => ({...acc,[k || "NONE"]:(acc[k || "NONE"] || 0) + v}),{"Not Required":0}) }),{} ) ), output = summary.flatMap( o => Object.keys(Object.values(o)[0]).map( z => ({ name: z === "NONE"? "": z, data: Object.keys(o).map(y => o[y][z]) }) ) ); console.log( output );