根據字典中的索引合並兩個字典列表

Question

這兩個是相關的數據集，但來自單獨的 json 文件，所以我想合並它們。 他們可以在索引上匹配，但我並沒有真正找到這樣做的好方法:)

字典列表 1：

[
  {'index': 217, 'name': 'Battery'}
  {'index': 218, 'name': 'Fluffy'}
  {'index': 219, 'name': 'Dazzling'}
  {'index': 220, 'name': 'Soul-Heart'}
]

字典清單 2：

[
  {'index': 217, 'desc': 'Text info 2'}
  {'index': 218, 'desc': 'will be very informative'}
  {'index': 219, 'desc': 'dont know what else i could write here'}
  {'index': 220, 'desc': 'Boosts my wallet'}
]

結果應該是這樣的：

[
  {'index': 217, 'name': 'Battery', 'desc': 'Text info 2'}
  {'index': 218, 'name': 'Fluffy', 'desc': 'will be very informative'}
  {'index': 219, 'name': 'Dazzling', 'desc': 'dont know what else i could write here'}
  {'index': 220, 'name': 'Soul-Heart', 'desc': 'Boosts my wallet'}
]

有更多的數據，但一旦我知道如何合並，我想我可以做 rest

Answer 1

Pandas 輕而易舉地處理合並。

首先將數據轉換為數據幀：

import pandas as pd

data1 = [
    {'index': 217, 'name': 'Battery'},
    {'index': 218, 'name': 'Fluffy'},
    {'index': 219, 'name': 'Dazzling'},
    {'index': 220, 'name': 'Soul-Heart'},
]
data2 = [
    {'index': 217, 'desc': 'Text info 2'},
    {'index': 218, 'desc': 'will be very informative'},
    {'index': 219, 'desc': 'dont know what else i could write here'},
    {'index': 220, 'desc': 'Boosts my wallet'},
]
df1 = pd.DataFrame(data1)
df2 = pd.DataFrame(data2)

然后在index列上合並：

df_out = df1.merge(df2, on='index')

看起來像這樣：

   index        name                                    desc
0    217     Battery                             Text info 2
1    218      Fluffy                will be very informative
2    219    Dazzling  dont know what else i could write here
3    220  Soul-Heart                        Boosts my wallet

• 文檔： pandas.DataFrame.merge()

然后轉換回字典列表：

df_out.to_dict(orient='records')

[{'index': 217, 'name': 'Battery', 'desc': 'Text info 2'},
 {'index': 218, 'name': 'Fluffy', 'desc': 'will be very informative'},
 {'index': 219, 'name': 'Dazzling', 'desc': 'dont know what else i could write here'},
 {'index': 220, 'name': 'Soul-Heart', 'desc': 'Boosts my wallet'}]

• 文檔： pandas.DataFrame.to_dict()

Answer 2

要合並 Python 中具有公共鍵值對的兩個字典，您可以對其中一個字典使用 update() 方法。 此方法將使用第二個字典中的值覆蓋公共鍵值對。

dict1.update(dict2)

這應該會給你預期的結果，但如果公共鍵值對不同，它將從第二個字典中挑選出來，第一個字典值將被覆蓋。

Answer 3

我假設index鍵中的值在每個列表中都是唯一的：

lst1 = [
    {"index": 217, "name": "Battery"},
    {"index": 218, "name": "Fluffy"},
    {"index": 219, "name": "Dazzling"},
    {"index": 220, "name": "Soul-Heart"},
]

lst2 = [
    {"index": 217, "desc": "Text info 2"},
    {"index": 218, "desc": "will be very informative"},
    {"index": 219, "desc": "dont know what else i could write here"},
    {"index": 220, "desc": "Boosts my wallet"},
]


tmp1 = {d["index"]: d["name"] for d in lst1}
tmp2 = {d["index"]: d["desc"] for d in lst2}

out = []
for k in tmp1.keys() & tmp2.keys():
    out.append(
        {"index": k, "name": tmp1.get(k, "N/A"), "desc": tmp2.get(k, "N/A")}
    )

print(out)

印刷：

[
    {"index": 217, "name": "Battery", "desc": "Text info 2"},
    {"index": 218, "name": "Fluffy", "desc": "will be very informative"},
    {
        "index": 219,
        "name": "Dazzling",
        "desc": "dont know what else i could write here",
    },
    {"index": 220, "name": "Soul-Heart", "desc": "Boosts my wallet"},
]

Answer 4

這會起作用，但效率很低，因為您必須遍歷每個列表的每個字典。 如果您能夠更改數據結構，這樣您就不會遍歷列表中的字典，那就更好了。 看看是否可以更改它，以便您擁有類似...

dicts2 = {
  217 : {'desc': 'Text info 2'},
  218 : {'desc': 'will be very informative'},
  219 : {'desc': 'dont know what else i could write here'},
  220 : {'desc': 'Boosts my wallet'}
}

通過這種方式，您可以利用 dict 作為數據結構並查找所需的項目，而不是遍歷每個項目（與列表一樣）

但這是您現在的解決方案：

dicts1 = [
  {'index': 217, 'name': 'Battery'},
  {'index': 218, 'name': 'Fluffy'},
  {'index': 219, 'name': 'Dazzling'},
  {'index': 220, 'name': 'Soul-Heart'}
]

dicts2 = [
  {'index': 217, 'desc': 'Text info 2'},
  {'index': 218, 'desc': 'will be very informative'},
  {'index': 219, 'desc': 'dont know what else i could write here'},
  {'index': 220, 'desc': 'Boosts my wallet'}
]

for d1 in dicts1:
    for d2 in dicts2:
        if d1['index'] == d2['index']:
            for key, value in d1.items():
                d2[key] = value
            
print(dicts2)
--------------------------------------------------------------
[
  {'index': 217, 'desc': 'Text info 2', 'name': 'Battery'}, 
  {'index': 218, 'desc': 'will be very informative', 'name': 'Fluffy'}, 
  {'index': 219, 'desc': 'dont know what else i could write here', 'name': 'Dazzling'}, 
  {'index': 220, 'desc': 'Boosts my wallet', 'name': 'Soul-Heart'}
]

Answer 5

要對列表執行此合並，請使用：

a = [{'index': 217, 'name': 'Battery'},{'index': 218, 'name': 'Fluffy'},{'index': 219, 'name': 'Dazzling'}, {'index': 220, 'name': 'Soul-Heart'}]

b = [{'index': 217, 'desc': 'Text info 2'},{'index': 218, 'desc': 'will be very informative'},{'index': 219, 'desc': 'dont know what else i could write here'},{'index': 220, 'desc': 'Boosts my wallet'}]


final_lst = []
for first, second in zip(a,b):
    first.update(second)
    final_lst.append(first)
print(final_lst)