Python 如何將字典列表中的特定鍵傳遞給 Map function

Question

我有以下格式的數據： 我有 function 接受 2 個關鍵字參數 我無法提供語法或示例，我可以將特定鍵從字典列表傳遞到 Map function 以作為多線程運行

import concurrent.futures

data = [
    {
        "name": "abc",
        "org": "pqr"
    },
    {
        "name": "xyz",
        "org": "sdf"
    }
    ]
def process_data(org_name, cu_name):
    print(org_name)
    print(cu_name)

with concurrent.futures.ThreadPoolExecutor() as Executor:
   results = Executor.map(process_data, data)

由於數據包含不同的密鑰，我需要 map org 到 org_name，但我不確定如何通過 map function

Answer 1

當您將數據用作map()中的可迭代對象時，將發生的是列表中的每個元素都將傳遞給 process_data。 那個function只接收一個參數。

所以...

from concurrent.futures import ThreadPoolExecutor as TPE

data = [
    {
        "name": "abc",
        "org": "pqr"
    },
    {
        "name": "xyz",
        "org": "sdf"
    }
]

def process_data(d):
    for k, v in d.items():
        print(f'{k} = {v}')

with TPE() as tpe:
    tpe.map(process_data, data)

...可能有助於澄清

Answer 2

讓您的process_data function 接受所需的鍵org和name ，這樣每個輸入字典就可以解壓（ ** ）到各自的鍵上：

def process_data(org, name):
    print(org, name)

with concurrent.futures.ThreadPoolExecutor() as Executor:
   results = Executor.map(lambda kargs: process_data(**kargs), data)

---

pqr abc
sdf xyz

Answer 3

    import concurrent.futures

data = [
    {
        "name": "abc",
        "org": "pqr"
    },
    {
        "name": "xyz",
        "org": "sdf"
    }
]


def process_data(org_name, cu_name):
    print(f'org = {org_name}')
    print(f'cu ={cu_name}')



with concurrent.futures.ThreadPoolExecutor() as Executor:
    result = Executor.map(lambda d: process_data(org_name=d['name'], cu_name=d['org']), data)

感謝邁克爾，這對我有用