Python 如何将字典列表中的特定键传递给 Map function

Question

我有以下格式的数据： 我有 function 接受 2 个关键字参数 我无法提供语法或示例，我可以将特定键从字典列表传递到 Map function 以作为多线程运行

import concurrent.futures

data = [
    {
        "name": "abc",
        "org": "pqr"
    },
    {
        "name": "xyz",
        "org": "sdf"
    }
    ]
def process_data(org_name, cu_name):
    print(org_name)
    print(cu_name)

with concurrent.futures.ThreadPoolExecutor() as Executor:
   results = Executor.map(process_data, data)

由于数据包含不同的密钥，我需要 map org 到 org_name，但我不确定如何通过 map function

Answer 1

当您将数据用作map()中的可迭代对象时，将发生的是列表中的每个元素都将传递给 process_data。 那个function只接收一个参数。

所以...

from concurrent.futures import ThreadPoolExecutor as TPE

data = [
    {
        "name": "abc",
        "org": "pqr"
    },
    {
        "name": "xyz",
        "org": "sdf"
    }
]

def process_data(d):
    for k, v in d.items():
        print(f'{k} = {v}')

with TPE() as tpe:
    tpe.map(process_data, data)

...可能有助于澄清

Answer 2

让您的process_data function 接受所需的键org和name ，这样每个输入字典就可以解压（ ** ）到各自的键上：

def process_data(org, name):
    print(org, name)

with concurrent.futures.ThreadPoolExecutor() as Executor:
   results = Executor.map(lambda kargs: process_data(**kargs), data)

---

pqr abc
sdf xyz

Answer 3

    import concurrent.futures

data = [
    {
        "name": "abc",
        "org": "pqr"
    },
    {
        "name": "xyz",
        "org": "sdf"
    }
]


def process_data(org_name, cu_name):
    print(f'org = {org_name}')
    print(f'cu ={cu_name}')



with concurrent.futures.ThreadPoolExecutor() as Executor:
    result = Executor.map(lambda d: process_data(org_name=d['name'], cu_name=d['org']), data)

感谢迈克尔，这对我有用