[英]Convert a IList<int> collection to a comma separated list
將IList集合轉換為逗號分隔id的字符串的任何優雅方式?
“1,234,2,324,324,2”
IList<int> list = new List<int>( new int[] { 1, 2, 3 } );
Console.WriteLine(string.Join(",", list));
你可以做:
// Given: IList<int> collection;
string commaSeparatedInts = string.Join(",",collection.Select(i => i.ToString()).ToArray());
這樣做
IList<int> strings = new List<int>(new int[] { 1,2,3,4 });
string[] myStrings = strings.Select(s => s.ToString()).ToArray();
string joined = string.Join(",", myStrings);
或完全與Linq
string aggr = strings.Select(s=> s.ToString()).Aggregate((agg, item) => agg + "," + item);
// list = IList<MyObject>
var strBuilder = new System.Text.StringBuilder();
foreach(var obj in list)
{
strBuilder.Append(obj.ToString());
strBuilder.Append(",");
}
strBuilder = strBuilder.SubString(0, strBuilder.Length -1);
return strBuilder.ToString();
List<int> intList = new List<int>{1,234,2,324,324,2};
var str = intList.Select(i => i.ToString()).Aggregate( (i1,i2) => string.Format("{0},{1}",i1,i2));
Console.WriteLine(str);
mstrickland對使用字符串構建器有一個好主意,因為它具有較大列表的速度。 但是,您不能將stringbuilder設置為字符串。 試試這個。
var strBuilder = new StringBuilder();
foreach (var obj in list)
{
strBuilder.Append(obj.ToString());
strBuilder.Append(",");
}
return strBuilder.ToString(0, strBuilder.Length - 1);
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