Java RSA加密 - 解密.NET

Question

我正在使用RSA加密JAVA並嘗試使用.NET解密。 我包含了我的JAVA代碼和.NET代碼，希望有人有這方面的經驗。

JAVA代碼：

byte[] modulusBytes = Base64.decode("xTSiS4+I/x9awUXcF66Ffw7tracsQfGCn6g6k/hGkLquHYMFTCYk4mOB5NwLwqczwvl8HkQfDShGcvrm47XHKUzA8iadWdA5n4toBECzRxiCWCHm1KEg59LUD3fxTG5ogGiNxDj9wSguCIzFdUxBYq5ot2J4iLgGu0qShml5vwk=");
byte[] exponentBytes = Base64.decode("AQAB");
BigInteger modulus = new BigInteger(1, modulusBytes );
BigInteger exponent = new BigInteger(1, exponentBytes);

RSAPublicKeySpec rsaPubKey = new RSAPublicKeySpec(modulus, exponent);
KeyFactory fact = KeyFactory.getInstance("RSA");
PublicKey pubKey = fact.generatePublic(rsaPubKey);

Cipher cipher = Cipher.getInstance("RSA");
cipher.init(Cipher.ENCRYPT_MODE, pubKey);

byte[] plainBytes = new String("big kitty dancing").getBytes("UTF-8");
byte[] cipherData = cipher.doFinal( plainBytes );
String encryptedString = Base64.encodeBytes(cipherData);

從這個JAVA代碼我得到的encryptedString的結果恰好是：

FoP4 + AAIH6hcabXnrvNG5YUk / nBv9n9HU0CAgZjkIWQIDjbOpSwoPVBFERrZ6641x2QaoJw5yv18XAay + 0WrCaSw4sveRX + hmPm5qeVUPcjoR4slsVZ / hBFJtAHj9tva4hOugWDZa9s3RVJlxkNfE + U +的Kt / YKLOi2EYbH05HjeM =

並嘗試使用以下.NET代碼進行解密

const int PROVIDER_RSA_FULL = 1;
const string CONTAINER_NAME = "Tracker";

CspParameters cspParams;
cspParams = new CspParameters(PROVIDER_RSA_FULL);
cspParams.KeyContainerName = CONTAINER_NAME;
RSACryptoServiceProvider rsa1 = new RSACryptoServiceProvider(cspParams);
rsa1.FromXmlString("<RSAKeyValue><Modulus>xTSiS4+I/x9awUXcF66Ffw7tracsQfGCn6g6k/hGkLquHYMFTCYk4mOB5NwLwqczwvl8HkQfDShGcvrm47XHKUzA8iadWdA5n4toBECzRxiCWCHm1KEg59LUD3fxTG5ogGiNxDj9wSguCIzFdUxBYq5ot2J4iLgGu0qShml5vwk=</Modulus><Exponent>AQAB</Exponent><P>+lXMCEwIN/7+eMpBrq87kQppxu3jJBTwztGTfXNaPUTx+A6uqRwug5oHBbSpYXKNDNCBzVm/0VxB3bo4FJx+ZQ==</P><Q>yasOGaJaE9xlF9T2xRuKeG9ZxCiyjhYaYB/mbtL+SIbtkRLi/AxaU4g2Il/UxhxhSXArKxIzV28zktispPJx1Q==</Q><DP>ueRgQIEFUV+fY979a1RgrVHIPpqEI1URhOMH3Q59oiXCcOumM5njyIHmWQxRAzXnG+7xlKXi1PrnRll0L4oOKQ==</DP><DQ>dfEMNgG1HJhwpxdtmqkYuoakwQvsIRzcIAuIAJh1DoWaupWJGk8/JEstHb1d+t7uJrzrAi2KyT/HscH2diE0YQ==</DQ><InverseQ>YoYF9PF6FiC0YngVeaC/eqt/ea8wMYNN3YO1LuzWpcy2exPRj2U0ZbWMvHXMUb4ea2qmhZGx1QlK4ULAuWKpXQ==</InverseQ><D>g1WAWI4pEK9TA7CA2Yyy/2FzzNiu0uQCuE2TZYRNiomo96KQXpxwqAzZLw+VDXfJMypwDMAVZe/SqzSJnFEtZxjdxaEo3VLcZ1mnbIL0vS7D6iFeYutF9kF231165qGd3k2tgymNMMpY7oYKjS11Y6JqWDU0WE5hjS2X35iG6mE=</D></RSAKeyValue>");

string data2Decrypt =    "FoP4+AAIH6hcabXnrvNG5YUk/nBv9n9HU0CAgZjkIWQIDjbOpSwoPVBFERrZ6641x2QaoJw5yv18XAay+0WrCaSw4sveRX+hmPm5qeVUPcjoR4slsVZ/hBFJtAHj9tva4hOugWDZa9s3RVJlxkNfE+u+Kt/YKLOi2EYbH05HjeM=";

byte[] encyrptedBytes = Convert.FromBase64String(data2Decrypt);  

byte[] plain = rsa1.Decrypt(encyrptedBytes, false);
string decryptedString = System.Text.Encoding.UTF8.GetString(plain);

Answer 1

在Java端，您需要使用"RSA/ECB/PKCS1Padding"作為算法名稱。 使用簡單的"RSA"名稱，Java不會添加C＃實現所期望的PKCS＃1填充，因此是“壞數據”。

填充是將輸入數據（您的編碼字符串）轉換為稍大的字符串，其長度與RSA模數相同（此處為128字節）。 它對於安全性很重要並且會注入一些隨機性（相同的輸入字符串不會每次產生相同的加密字符串;但解密過程會刪除該隨機性並恢復正確的字符串）。