[英]How to query XML nodes based on the value of the attribute of its parent node
我有一個看起來像這樣的XML：
<Library>
<Author Name = "JRR Tolkien">
<Book Title = "Lord Of the Rings" />
<Book Title = "The Hobbit" />
</Author>
<Author Name = "JK Rowling">
<Book Title = "Harry Potter and the Sorcerers Stone" />
<Book Title = "Harry Potter and the Prisoner of Azkaban" />
</Author>
</Library>
XPath是什么，用於選擇其父“ Author”節點的值為“ JK Rowling”的所有“ Book”節點？
這是最直觀，最嚴格的選擇，將所有具有“ Author Name屬性為'JK Rowling' Author 'JK Rowling'選為父本。 並且Author還必須擁有Library作為父母。
/Library/Author[@Name='JK Rowling']/Book
如何遍歷XML中的所有節點並根據C＃中的值更改節點值？
[英]How to loop through all nodes in XML and change node value based on its value in C#?
如何根據XML文檔的屬性值和XElement對象從XML文檔中獲取節點？
[英]How can I get a node from an XML document based on its attribute value and into an XElement object?
使用LINQ to XML基於屬性與多個節點來獲取正確的節點
[英]Grabbing correct node based on attribute with multiple nodes using LINQ to XML
Linq XML查詢-如何返回在其自己的嵌套節點中滿足條件的節點？
[英]Linq XML query - How do I return a node that meets a condition within its own nested nodes?
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