[英]How do I validate an Australian Medicare number?
我正在開發一個在線表格,其中需要驗證用戶輸入的醫療保險號碼。
(我的具體問題涉及澳大利亞醫療保險號碼,但我也很高興得到有關美國醫療保險號碼的答案。這個問題是關於一般醫療保險號碼的。)
那我應該怎么做呢?
(最好用 Javascript 或正則表達式來回答。)
Jeffrey Kemp(3 月 11 日)提供的正則表達式將有助於驗證允許的字符,但下面的檢查算法應該足以驗證數字是否符合 Medicare 的規則。
Medicare 卡號包括:
注意:Medicare 卡號的第一位數字應在 2 到 6 之間。
醫保卡號校驗位計算
其中第 1 位是 Medicare 卡號的最高位值數字,第 8 位是 Medicare 卡號的最低位值位。
示例:對於 Medicare 卡號“2123 45670 1”,數字 1 為 2,數字 8 為 7。
示例:對於 Medicare 卡號 2123 4567。
來源:“在健康軟件系統中使用醫療保健標識符 - 軟件一致性要求,版本 1.4”,NEHTA,3/05/2011
如果您正在尋找 C# 版本,請嘗試一下:
using System.Linq;
//...
public bool IsMedicareFormatValid(string medicareNumber)
{
if (!(medicareNumber?.Length >= 10 && medicareNumber.Length <12) || !medicareNumber.All(char.IsDigit))
return false;
var digits = medicareNumber.Select(c => (int) char.GetNumericValue(c)).ToArray();
return digits[8] == GetMedicareChecksum(digits.Take(8).ToArray());
}
private int GetMedicareChecksum(int[] digits)
{
return digits.Zip(new[] { 1, 3, 7, 9, 1, 3, 7, 9 }, (m, d) => m*d).Sum() % 10;
}
注意:對於空值,這將返回 false,您可能想要拋出異常。
澄清:
GetMedicareChecksum
方法中計算的校驗位。希望有人覺得這很有用。
這是一個 Typescript 或現代 Javascript 解決方案:
validateMedicare(medicare) {
let isValid = false;
if (medicare && medicare.length === 10) {
const matches = medicare.match(/^(\d{8})(\d)/);
if (!matches) {
return { invalid: true };
}
const base = matches[1];
const checkDigit = matches[2];
const weights = [1, 3, 7, 9, 1, 3, 7, 9];
let sum = 0;
for (let i = 0; i < weights.length; i++) {
sum += parseInt(base[i], 10) * weights[i];
}
isValid = sum % 10 === parseInt(checkDigit, 10);
}
return isValid;
}
請參閱http://clearwater.com.au/code/medicare以獲得解釋。
要進行測試,請在此處生成醫療保險編號: https : //precedencehealthcare.com/rmig/
添加了 Swift 版本
class func isMedicareValid(input : String, validateWithIrn : Bool) -> Bool {
let multipliers = [1, 3, 7, 9, 1, 3, 7, 9]
let pattern = "^(\\d{8})(\\d)"
let medicareNumber = input.removeWhitespace()
let length = validateWithIrn ? 11 : 10
if medicareNumber.characters.count != length {return false}
let expression = try! NSRegularExpression(pattern: pattern, options: NSRegularExpressionOptions.CaseInsensitive)
let matches = expression.matchesInString(medicareNumber, options: NSMatchingOptions.ReportProgress, range: NSMakeRange(0, length))
if (matches.count > 0 && matches[0].numberOfRanges > 2) {
let base = medicareNumber.substringWithRange(medicareNumber.startIndex...medicareNumber.startIndex.advancedBy(matches[0].rangeAtIndex(1).length))
let checkDigitStartIndex = medicareNumber.startIndex.advancedBy(matches[0].rangeAtIndex(2).location )
let checkDigitEndIndex = checkDigitStartIndex.advancedBy(matches[0].rangeAtIndex(2).length)
let checkDigit = medicareNumber.substringWithRange(checkDigitStartIndex..<checkDigitEndIndex)
var total = 0
for i in 0..<multipliers.count {
total += Int(base.charAtIndex(i))! * multipliers[i]
}
return (total % 10) == Int(checkDigit)
}
return false
}
我也使用一些字符串擴展來簡化一些操作。
extension String {
func charAtIndex (index: Int) -> String{
var character = ""
if (index < self.characters.count){
let locationStart = self.startIndex.advancedBy(index)
let locationEnd = self.startIndex.advancedBy(index + 1 )
character = self.substringWithRange(locationStart..<locationEnd)
}
return character
}
func replace(string:String, replacement:String) -> String {
return self.stringByReplacingOccurrencesOfString(string, withString: replacement, options: NSStringCompareOptions.LiteralSearch, range: nil)
}
func removeWhitespace() -> String {
return self.replace(" ", replacement: "")
}
}
添加了 Java 版本
public static boolean isMedicareValid(String input, boolean validateWithIRN){
int[] multipliers = new int[]{1, 3, 7, 9, 1, 3, 7, 9};
String pattern = "^(\\d{8})(\\d)";
String medicareNumber = input.replace(" " , "");
int length = validateWithIRN ? 11 : 10;
if (medicareNumber.length() != length) {return false;}
Pattern medicatePattern = Pattern.compile(pattern);
Matcher matcher = medicatePattern.matcher(medicareNumber);
if (matcher.find()){
String base = matcher.group(1);
String checkDigit = matcher.group(2);
int total = 0;
for (int i = 0; i < multipliers.length; i++){
total += base.charAt(i) * multipliers[i];
}
return ((total % 10) == Integer.parseInt(checkDigit));
}
return false;
}
我的澳大利亞醫療保險號碼是 11 位數字,不包含字母或其他字符。
它是按組格式化的,最后一位數字因我的家庭成員而異,例如:
5101 20591 8-1
5101 20591 8-2
5101 20591 8-3
我見過格式不帶空格和破折號的醫療保險號碼,但含義是一樣的,所以我希望也接受51012059181
作為有效的醫療保險號碼。
我還看到了不需要或不應該輸入最后一位數字的上下文; 例如5101205918
,我猜他們只對整個家庭感興趣。
因此,我認為這可能是合適的:
^\d{4}[ ]?\d{5}[ ]?\d{1}[- ]?\d?$
編輯
根據 user2247167 的回答中的邏輯,我在我的 Apex 應用程序中使用了以下 PL/SQL 函數來向用戶發出用戶友好的警告:
FUNCTION validate_medicare_no (i_medicare_no IN VARCHAR2)
RETURN VARCHAR2 IS
v_digit1 CHAR(1);
v_digit2 CHAR(1);
v_digit3 CHAR(1);
v_digit4 CHAR(1);
v_digit5 CHAR(1);
v_digit6 CHAR(1);
v_digit7 CHAR(1);
v_digit8 CHAR(1);
v_check CHAR(1);
v_result NUMBER;
BEGIN
IF NOT REGEXP_LIKE(i_medicare_no, '^\d{10}\d?{2}$') THEN
RETURN 'Must be 10-12 digits, no spaces or other characters';
ELSE
v_digit1 := SUBSTR(i_medicare_no, 1, 1);
IF v_digit1 NOT IN ('2','3','4','5','6') THEN
RETURN 'Not a valid Medicare number - please check and re-enter';
ELSE
v_digit2 := SUBSTR(i_medicare_no, 2, 1);
v_digit3 := SUBSTR(i_medicare_no, 3, 1);
v_digit4 := SUBSTR(i_medicare_no, 4, 1);
v_digit5 := SUBSTR(i_medicare_no, 5, 1);
v_digit6 := SUBSTR(i_medicare_no, 6, 1);
v_digit7 := SUBSTR(i_medicare_no, 7, 1);
v_digit8 := SUBSTR(i_medicare_no, 8, 1);
v_check := SUBSTR(i_medicare_no, 9, 1);
v_result := mod( to_number(v_digit1)
+ (to_number(v_digit2) * 3)
+ (to_number(v_digit3) * 7)
+ (to_number(v_digit4) * 9)
+ to_number(v_digit5)
+ (to_number(v_digit6) * 3)
+ (to_number(v_digit7) * 7)
+ (to_number(v_digit8) * 9)
,10);
IF TO_NUMBER(v_check) != v_result THEN
RETURN 'Not a valid Medicare number - please check and re-enter';
END IF;
END IF;
END IF;
-- no error
RETURN NULL;
END validate_medicare_no;
接受的答案,適用於 JavaScript:
var validator = function (input, validateWithIrn) {
if (!input) {
return false;
}
var medicareNumber;
var pattern;
var length;
var matches;
var base;
var checkDigit;
var total;
var multipliers;
var isValid;
pattern = /^(\d{8})(\d)/;
medicareNumber = input.toString().replace(/ /g, '');
length = validateWithIrn ? 11 : 10;
if (medicareNumber.length === length) {
matches = pattern.exec(medicareNumber);
if (matches) {
base = matches[1];
checkDigit = matches[2];
total = 0;
multipliers = [1, 3, 7, 9, 1, 3, 7, 9];
for (var i = 0; i < multipliers.length; i++) {
total += base[i] * multipliers[i];
}
isValid = (total % 10) === Number(checkDigit);
} else {
isValid = false;
}
} else {
isValid = false;
}
return isValid;
};
我找到了關於這個主題的論壇討論:
http://regexadvice.com/forums/thread/57337.aspx
我打算嘗試一下'澳洲蘇珊'想出的:
^\d{9}B[ADGHJKLNPQRTWY1-9,]?$
您可以創建驗證屬性來驗證醫療保險號碼
您可以通過以下方式使用它
[AustralianMedicareNumberOnly]
public string MedicareNo { get; set; }
代碼
public class AustralianMedicareNumberOnlyAttribute : ValidationAttribute
{
private string exampleNumber = "Example: 2234 56789 1-2";
public AustralianMedicareNumberOnlyAttribute()
{
ErrorMessage = string.Concat("{0} is not in correct format, ", exampleNumber);
}
protected override ValidationResult IsValid(object value, ValidationContext validationContext)
{
if (value != null)
{
string objectValueString;
int[] checksumDigits = new int[] { 1, 3, 7, 9, 1, 3, 7, 9 };
int checksumDigit;
int checksumtotal = 0;
int checksumDigitCalculated;
//convert incomming object value to string
objectValueString = Convert.ToString(value).Trim();
// check medicare number format should be 1234 56789 1-2
if (!Regex.IsMatch(objectValueString, @"^[2-6]\d{3}\s\d{5}\s\d{1}-\d{1}$"))
{
return new ValidationResult(FormatErrorMessage(validationContext.DisplayName));
}
else
{
//Check checksum value
//--------------------
// replace two spaces and one dash
objectValueString = objectValueString.Replace(" ", "").Replace("-", "");
// Calculate the sum of: ((digit 1) + (digit 2 * 3) + (digit 3 * 7) + (digit 4 * 9) + (digit 5) + (digit 6 * 3) + (digit 7 * 7) + (digit 8 * 9))
for (int i = 0; i < checksumDigits.Length; i++)
{
int digit = Convert.ToInt32(objectValueString.Substring(i, 1));
checksumtotal += digit * checksumDigits[i];
}
//find out checksum digit
checksumDigit = Convert.ToInt32(objectValueString.Substring(8, 1));
checksumDigitCalculated = checksumtotal % 10;
// check calculated checksum with medicare checksum digit
if (checksumDigit!= checksumDigitCalculated)
{
return new ValidationResult("The Medicare Number is not Valid.");
}
}
}
return ValidationResult.Success;
}
}
添加了 Dart 版本:
bool isMedicareValid(String input, {bool validateWithIrn = true}) {
final medicareNumber = input.replaceAll(" ", "");
final length = validateWithIrn ? 11 : 10;
if (medicareNumber.length != length) {
return false;
}
final multipliers = [1, 3, 7, 9, 1, 3, 7, 9];
final regexp = RegExp("^(\\d{8})(\\d)", caseSensitive: false);
final matches = regexp.allMatches(medicareNumber).toList();
if (matches.length > 0 && matches[0].groupCount >= 2) {
final base = matches[0].group(1);
final checkDigit = matches[0].group(2);
var total = Iterable.generate(multipliers.length)
.fold(0, (current, index) => current += (int.tryParse(base[index]) * multipliers[index]));
return (total % 10) == int.parse(checkDigit);
}
return false;
}
另一個帶有注釋的 Swift 實現:
func validateMedicareNumber(input: String) -> Bool {
let weights = [1, 3, 7, 9, 1, 3, 7, 9]
// Remove all whitespace
var trimmed = input.trimmingCharacters(in: .whitespacesAndNewlines)
.components(separatedBy: .whitespaces)
.joined()
// The medicare card number has 8 digits identifier + 1 digit checksum + 1 digit issue number.
// Either 9 or 10 numbers will be valid
guard trimmed.count == 9 || trimmed.count == 10 else {
return false
}
// Drop the issue number if it was added
if trimmed.count == 10 {
trimmed = String(trimmed.dropLast())
}
// The last digit is a checksum
guard let lastElement = trimmed.last,
let checkSum = Int(String(lastElement)) else {
return false
}
// Remove the checksum from our input
trimmed = String(trimmed.dropLast())
// Multiply the numbers by weights
let weightedNumbers: [Int] = trimmed.enumerated().map { index, element in
guard let number = Int(String(element)) else {
// -1 will throw the calculations out of the window which
// will guarantee invalid checksum
return -1
}
return number * weights[index]
}
// Validate the weighted numbers against the checksum
return weightedNumbers.reduce(0, +) % 10 == checkSum
}
如果您需要用於開發的測試卡號,請使用此卡號。 這是給約翰·多伊的
測試卡號 > 2428 77813 2/1
擴展Daniel Ormeño 的答案,對於 asp.net,您可以將支票放入一個屬性中並在模型中裝飾該屬性
public class MedicareValidation : ValidationAttribute
{
public override bool IsValid(object value)
{
string medicareNumber = value.ToString();
if (!(medicareNumber?.Length >= 10 && medicareNumber.Length < 12) || !medicareNumber.All(char.IsDigit))
return false;
var digits = medicareNumber.Select(c => (int)char.GetNumericValue(c)).ToArray();
return digits[8] == GetMedicareChecksum(digits.Take(8).ToArray());
}
private int GetMedicareChecksum(int[] digits)
{
return digits.Zip(new[] { 1, 3, 7, 9, 1, 3, 7, 9 }, (m, d) => m * d).Sum() % 10;
}
}
然后在模型中
[DisplayName("Medicare Number")]
[MedicareValidation]
public string MedicareNumber {get; set;}
這是一個 Python 版本! 請注意,它需要一個完整的 11 位醫療保險號碼。 如果您要驗證 10 位醫療保險號碼而沒有個人參考號碼,則需要調整re.match
行中的正則表達式。
def validate_medicare_number(medicare_number: str) -> bool:
"""Given a string containing a medicare number, return True if valid,
False if invalid.
>>> validate_medicare_number("2428 77813 2/1")
True
>>> validate_medicare_number("7428 77818 2/1")
False
>>> validate_medicare_number("2428 77815 2/1")
False
"""
# See here for checksum algorithm:
# https://stackoverflow.com/a/15823818
# https://clearwater.com.au/code/medicare
# Remove whitespace
medicare_number = re.sub(r"[^\d]+", "", medicare_number)
if re.match(r"^[2-6]\d{10}$", medicare_number):
medicare_digits = list(map(int, medicare_number))
checksum_weights = (1, 3, 7, 9) * 2
digit_weight_pairs = zip(medicare_digits, checksum_weights)
checksum = sum([digit * weight for digit, weight in digit_weight_pairs]) % 10
return checksum == medicare_digits[8]
else:
return False
假設輸入的醫療保險號是干凈的。 驗證10 位醫療保險號碼。 不包括參考編號。
if object_id('dbo.validate_medicare') is not null
drop function dbo.validate_medicare;
go
create function dbo.validate_medicare(@medicareNumber varchar(max))
returns int
as
begin
if len(@medicareNumber) <> 10
return 0;
if isnumeric(@medicareNumber) = 0
return 0;
declare @count as int = 0;
declare @firstDigit as int = cast(substring(@medicareNumber, 1, 1) as int);
if @firstDigit not between 2 and 6
return 0;
declare @actualCheckDigit as int = cast(substring(@medicareNumber, 9, 1) as int);
declare @computedCheckDigit as int;
declare @weight as int = 1;
declare @tempStuff table (
digit int,
weight int
);
declare @isValid as int;
while @count < len(substring(@medicareNumber, 1, 8))
begin
declare @selected_digit as int = substring(@medicareNumber, @count+1, 1);
if @weight > 9
set @weight = 1;
insert into @tempStuff(digit, weight) values (@selected_digit, @weight);
set @weight = @weight + 2;
if @weight = 5
set @weight = @weight + 2;
set @count = @count + 1;
end;
-- Set the computed Check digit
select @computedCheckDigit = (sum(digit * weight)) % 10 from @tempStuff;
-- Check if computed check digit equals the actual check digit
set @isValid = case
when @computedCheckDigit = @actualCheckDigit
then 1
else 0
end;
return @isValid;
end;
go
declare @medicareNumber as varchar(11) = '2123456701';
select dbo.validate_medicare(@medicareNumber) as IsValid;
您可以使用簡單的正則表達式驗證: .replace(/\\W/gi, "") .replace(/(.{4})(.{5})/g, "$1 $2 ");
在此處查看我的示例: codeandbox.io
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