WM_KEYDOWN，從lparam獲取值？

Question

在MSDN上，對於WM_KEYDOWN定義，它說lparam的位包含：

Bits    Meaning
0-15    The repeat count for the current message. The value is the number of times the keystroke is autorepeated as a result of the user holding down the key. If the keystroke is held long enough, multiple messages are sent. However, the repeat count is not cumulative.
16-23   The scan code. The value depends on the OEM.
24  Indicates whether the key is an extended key, such as the right-hand ALT and CTRL keys that appear on an enhanced 101- or 102-key keyboard. The value is 1 if it is an extended key; otherwise, it is 0.
25-28   Reserved; do not use.
29  The context code. The value is always 0 for a WM_KEYDOWN message.
30  The previous key state. The value is 1 if the key is down before the message is sent, or it is zero if the key is up.
31  The transition state. The value is always 0 for a WM_KEYDOWN message.

（ http://msdn.microsoft.com/en-us/library/ms646280%28VS.85%29.aspx ）

所以我創建了一個帶有結構的聯合，如下所示：

union KeyState
{
    LPARAM lparam;

    struct
    {
        unsigned nRepeatCount : 15;
        unsigned nScanCode : 8;
        unsigned nExtended : 1;
        unsigned nReserved : 4;
        unsigned nContext : 1;
        unsigned nPrev : 1;
        unsigned nTrans : 1;
    };
};

然后，當我在編輯框中收到wm_keydown消息時，我將其打印出來：

if (msg == WM_KEYDOWN)
{
    std::tstringstream ss;

    KeyState ks;
    ks.lparam = lparam;

    ss << "Key: " << (TCHAR)wparam << ", Val: " << (UINT)wparam << ", nRepeatCount: " << ks.nRepeatCount << 
        ", nScanCode: " << ks.nScanCode << ", nExtended: " << ks.nExtended << ", nReserved: " << ks.nReserved << 
        ", nContext: " << ks.nContext << ", nPrev: " << ks.nPrev << ", nTrans: " << ks.nTrans;

    SetWindowText(hOut, ss.str().c_str());
}

我在編輯框中輸入時返回的值似乎不正確，有時nReserved甚至是1或0，nRepeatCount總是1，無論我按住鍵記錄時間還是按下隨機密鑰。

我做錯了什么嗎？ 如果是這樣，從LPARAM獲得這些值的理想方法是什么？

Answer 1

嗯，一方面0-15是16位，而不是15位。

Answer 2

是的，很容易出錯（參見500的回答）。 我只想使用位圖和位移。

例如。 NRepeat = lparam＆0xFFFF;