在Java中將十六進制字符串轉換為ASCII

Question

我希望這不是一個愚蠢的問題，我在Google搜索結果的5個不同頁面上進行了瀏覽，但未能在此找到任何內容。

我需要做的是例如將包含所有十六進制字符的字符串轉換為ASCII

String fileName = 

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

我所見過的每一種方式似乎都必須先將其放入數組中。 沒有辦法遍歷每兩個循環並將它們轉換嗎？

Answer 1

只需使用for循環遍歷字符串中的每個字符，將它們轉換為字符，然后在字符串生成器的末尾重擊該字符：

String hex = "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";
StringBuilder output = new StringBuilder();
for (int i = 0; i < hex.length(); i+=2) {
    String str = hex.substring(i, i+2);
    output.append((char)Integer.parseInt(str, 16));
}
System.out.println(output);

或者（Java 8+）如果您感到特別不舒服，請使用臭名昭著的“固定寬度字符串拆分” hack來使您對流進行單線處理：

System.out.println(Arrays
        .stream(hex.split("(?<=\\G..)")) //https://stackoverflow.com/questions/2297347/splitting-a-string-at-every-n-th-character
        .map(s -> Character.toString((char)Integer.parseInt(s, 16)))
        .collect(Collectors.joining()));

無論哪種方式，這都會以以下幾行開頭：

uTorrent \\ Completed \\ nfsuc_ost_by_mustang \\ Pendulum-9,000 Miles.mp3

嗯... :-)

Answer 2

使用javax.xml.bind.DatatypeConverter最簡單方法：

    String hex = "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";
    byte[] s = DatatypeConverter.parseHexBinary(hex);
    System.out.println(new String(s));

Answer 3

String hexToAscii(String s) {
  int n = s.length();
  StringBuilder sb = new StringBuilder(n / 2);
  for (int i = 0; i < n; i += 2) {
    char a = s.charAt(i);
    char b = s.charAt(i + 1);
    sb.append((char) ((hexToInt(a) << 4) | hexToInt(b)));
  }
  return sb.toString();
}

private static int hexToInt(char ch) {
  if ('a' <= ch && ch <= 'f') { return ch - 'a' + 10; }
  if ('A' <= ch && ch <= 'F') { return ch - 'A' + 10; }
  if ('0' <= ch && ch <= '9') { return ch - '0'; }
  throw new IllegalArgumentException(String.valueOf(ch));
}

Answer 4

簽出使用Java將十六進制轉儲的字符串表示形式轉換為字節數組嗎？

忽略編碼等，您可以創建new String (hexStringToByteArray("75546..."));

Answer 5

因此，據我所知，您需要提取連續的十六進制數字對，然后解碼該2位數的十六進制數字並采用相應的char：

String s = "...";
StringBuilder sb = new StringBuilder(s.length() / 2);
for (int i = 0; i < s.length(); i+=2) {
    String hex = "" + s.charAt(i) + s.charAt(i+1);
    int ival = Integer.parseInt(hex, 16);
    sb.append((char) ival);
}
String string = sb.toString();

Answer 6

//%%%%%%%%%%%%%%%%%%%%%% HEX to ASCII %%%%%%%%%%%%%%%%%%%%%%
public String convertHexToString(String hex){

 String ascii="";
 String str;

 // Convert hex string to "even" length
 int rmd,length;
 length=hex.length();
 rmd =length % 2;
 if(rmd==1)
 hex = "0"+hex;

  // split into two characters
  for( int i=0; i<hex.length()-1; i+=2 ){

      //split the hex into pairs
      String pair = hex.substring(i, (i + 2));
      //convert hex to decimal
      int dec = Integer.parseInt(pair, 16);
      str=CheckCode(dec);
      ascii=ascii+" "+str;
  }
  return ascii;
}

public String CheckCode(int dec){
  String str;

          //convert the decimal to character
        str = Character.toString((char) dec);

      if(dec<32 || dec>126 && dec<161)
             str="n/a";  
  return str;
}

Answer 7

對於這種情況，我將十六進制數據格式轉換為int數組，並且希望將其轉換為String。

int[] encodeHex = new int[] { 0x48, 0x65, 0x6c, 0x6c, 0x6f }; // Hello encode
for (int i = 0; i < encodeHex.length; i++) {
   System.out.print((char) (encodeHex[i]));
}